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olga_2 [115]
3 years ago
9

What is the function of stomata in plants?

Chemistry
1 answer:
melomori [17]3 years ago
6 0

Answer:

Small holes in plants that allow carbon dioxide in and oxygen and water vapor out

Explanation:

Stomata are tiny holes that open and close for the plant to breathe.

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A stock solution of FeCl2 is available to prepare solutions that are more dilute. Calculate the volume, in mL, of a 2.0-M soluti
Harman [31]

Answer:

31.5mL

Explanation:

The following were obtained from the question:

C1 (concentration of stock solution) = 2M

V1 (volume of stock solution) =.?

C2 (concentration of diluted solution) = 0.630M

V2 (volume of diluted solution) = 100mL

Using the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

C1V1 = C2V2

2 x V1 = 0.630 x 100

Divide both side by 2

V1 = (0.630 x 100) /2

V1 = 31.5mL

Therefore, 31.5mL of 2M solution of FeCl2 required

7 0
3 years ago
Read 2 more answers
Given the atomic mass of select elements, calculate the molar mass of each salt.
den301095 [7]
1. 184.11
2. 168.812
3. 218.13
4. 272.21
8 0
3 years ago
How many liters of H2 gas would you have if you have 2.52 moles of H2?
mixer [17]
1 mol is 22.4L
2.52 moles are 2.52*22.4=56.4 L
7 0
3 years ago
2.) In a series of experiments, a chemist prepared three different compounds that contain only iodine and fluorine. He then dete
kaheart [24]

Answer:

compound 1 = 0.749gF / 1.0gl

compound 2 = 0.4489gF / 1.0gl

compound 3 = 1.047gF / 1.0gl

Explanation:

Given that;

compound       mass of iodine in grams          mass of fluorine in grams

       1                              4.75                                             3.56

       2                             7.64                                             3.43

       3                             9.41                                              9.86

a) Calculate the mass of fluorine per gram of iodine in each compound:

- compound 1

mass of Fluorine = (3.56gF / 4.75gF) * 1.0gl

= 0.749gF

Now RATIO = 0.749gF / 1.0gl

- compound 2

mass of Fluorine = (3.43gF / 7.64gF) * 1.0gl

= 0.4489gF

Now RATIO = 0.4489gF / 1.0gl

- compound 3

mass of Fluorine = (9.86gF / 9.41gF) * 1.0gl

= 1.047gF

Now RATIO = 1.047gF / 1.0gl

8 0
3 years ago
It is hard to identify a _____ strictly by color because many of them look so much alike.
vlada-n [284]

Answer:

Mineral

Explanation:

Many minerals share the same colors so it would be one of the least important parts of mineral identification

8 0
3 years ago
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