Let's convert the problem into Arithmetic progression:
It would be: 5, 9, 13, ....
Here, a = 5, d = 9 - 5 = 4
We know, S(n) = n/2 [ 2a + (n-1)d ]
Substitute the known values,
434 = n/2 [ 2(5) + (n - 1)4 ]
434 * 2 = n [ 10 + 4n - 4 ]
868 = 10n + 4n² - 4n
= 4n² + 6n - 868 = 0
d = b² - 4ac
d = 6² - 4(4)(-868)
d = 36+13888
d = 13924
Now, roots = -b +- √d / 2a
= (-6 + √13924) / 2(4) OR (-6 - √13924) / 2(4)
= (-6 + 118) / 8 OR (-6 - 118) / 8
= 112/8 OR -124/8
= 14 OR -15.5
As number of sticks can't be in negative/decimal or fraction form, -15.5 would be fully rejected.
In short, Your Answer would be 14 [ Remaining root ]
Hope this helps!
The only factor that both terms have is d
Answer:
Step-by-step explanation:
Both angles are supplementary (they add up to 180°)
This means that (10x) + (6x - 12°) = 180°
(10x) + (6x - 12°) = 180°
10x + 6x - 12° = 180°
16x - 12° = 180°
16x = 192°
x = 12°
Hope this helps!
Answer:
10
Step-by-step explanation:
its 5+5
Answer:
176 square yards
Step-by-step explanation:
<u><em>The picture of the question in the attached figure N 1</em></u>
we know that
The area of the walkway around the rectangular pool, is equal to the area of two trapezoids (#1 and #2), plus the area of two smaller rectangles (#3 and #4)
see the attached figure N 2 to better understand the problem
step 1
Find the area of the two trapezoids (#1 and #2)
![A=2[\frac{1}{2}(b_1+b_2)h]](https://tex.z-dn.net/?f=A%3D2%5B%5Cfrac%7B1%7D%7B2%7D%28b_1%2Bb_2%29h%5D)
simplify

we have

substitute

step 2
Find the area of the two smaller rectangles (#3 and #4)
![A=2[LW]](https://tex.z-dn.net/?f=A%3D2%5BLW%5D)
we have

substitute
![A=2[(4)(6)]=48\ yd^2](https://tex.z-dn.net/?f=A%3D2%5B%284%29%286%29%5D%3D48%5C%20yd%5E2)
step 3
Find the area of the walkway around the rectangular pool
