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3 years ago

5

The regression equation relating attitude rating (x) and job performance rating (y) for the employees of a company is Ten pairs

of data were used to obtain the equation. The same data yield r = 0.863 and
What is the best predicted job performance rating for a person whose attitude rating is 77?

80.1

12.6

88.9

90.2

1 answer:

Natalija [7]3 years ago

4 0

Answer:

The correct option is 90.2.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

<em>y</em> = dependent variable

<em>x</em> = independent variable

<em>α</em> = intercept

<em>β</em> = slope

The regression equation relating attitude rating (<em>x</em>) and job performance rating (<em>y</em>) for the employees of a company is:

$y=11.7+1.02x$

In this case the dependent variable is the job performance rating for the employees of a company and the independent variable is their attitude rating.

This implies that the for an employee of the company the job performance rating is based on their attitude towards work.

Compute the value of <em>y</em> for <em>x</em> = 77 as follows:

$y=11.7+1.02x$

$=11.7+(1.02\times 77)\\=11.7+78.54\\=90.24\\\approx90.2$

The predicted value of job performance rating for a person whose attitude rating is 77 is 90.2.

Thus, the correct option is 90.2.

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The amount of money earned, in compound interest, after t years, is given by:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

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A(t) is the amount of money after t years.

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n is the number of times that interest is compounded per year.

Hence, for Lincoln, we have that the parameters are as follows:

P = 49000, r = 0.06125, n = 365, t = 20.

Hence the amount will be of:

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$A_L(20) = 49000\left(1 + \frac{0.06125}{365}\right)^{365 \times 20}$

$A_L(20) = 166787$

<h3>What is continuous compounding?</h3>

The amount is given by:

$A(t) = Pe^{rt}$

For Eli, we have that r = 0.05625, hence the amount will be given by:

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$D = A_L(20) - A_E(20) = 166787 - 150931 = 15856$

Lincoln would have $15,856 more in his account than Eli.

More can be learned about compound interest at brainly.com/question/25781328

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Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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This means that there is a 0.04% .probability that 35 cars chosen at random will have a mean load weight of less than 49.5 tons of coal

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