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3 years ago

Photo above. please help!

Mathematics

2 answers:

choli [55]3 years ago

7 0

This is a proportion. You need to be able to find the missing value based on the information they've provided you with.

Here's the best way to solve ⇒

2/3 = x/48
Cross multiply them. ⇔ 2*48 = 3x
96 = 3x
x = 32

the missing value is 32

a_sh-v [17]3 years ago

3 0

Cross multiplication!
Because it is a proportion
$\frac{2}{3}$ = $\frac{?}{48}$
2 × 48 = 3 × ?
96 = 3 × ?
Divide by 3 on both sides to isolate the unknown number
$\frac{96}{3}$ = $\frac{3 * ?}{3}$
3 and 3 cancels out

32 = ?
The unknown number is 32

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A pair of parallel lines is cut by a transversal. What is the measure of angle x?

lina2011 [118]

Answer:

50° is the correct answer

Step-by-step explanation:

85=x+35

x=85-35

x=50

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3 years ago

Item 4 In a circle with a radius of 36.9 m, an arc is intercepted by a central angle of 8π 5 radians. What is the arc length? Us

leva [86]

Answer:

The arc length is 185.39 meters.

Step-by-step explanation:

The arc length is calculated by the following expression:

$\Delta s = \Delta \theta \cdot r$

Where:

$r$ - Radius, measured in meters.

$\Delta \theta$ - Central angle, measured in radians.

If $r = 36.9\,m$ and $\Delta \theta =\frac{8}{5}\pi\, rad$ , the arc length, measured in meters, is:

$\Delta s = \frac{8}{5}\pi\cdot (36.9\,m)$

$\Delta s = \frac{8}{5}\cdot (3.14)\cdot (36.9\,m)$

$\Delta s \approx 185.386\,m$

$\Delta s \approx 185.39\,m$

The arc length is 185.39 meters.

5 0

3 years ago

Describe the locus in space. points 4 mm from AB

ikadub [295]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

An object is launched from a platform. It's height (in meters), x seconds after the launch, is modeled by: h(x)=-5(x-4)^2+180. W

Kipish [7]

The height of the object at the time of launch is 100 meters.

To find this, we simply have to put 0 in for x, as this is when there has been no time (at launch)

h(x)=-5(x-4)^2+180

h(0)=-5(0-4)^2+180

h(0)=-5(-4)^2+180

h(0)=-5(16)+180

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h(0) = 100

7 0

4 years ago

For a lower tail hypothesis test with a sample size of 10 and a .10 level of significance, the critical value of the test statis

Fynjy0 [20]

Using a t-distribution calculator, it is found that the critical value of the test statistic t is $t^{\ast} = -1.383$ .

<h3>How to find the critical value of a t-test?</h3>

The critical value is found using a calculator.

The inputs are:

The tail.

The amount of degrees of freedom, which is one less than the sample size.

The significance level.

In this problem, we have a<u> lower(left-tailed) test, with 10 - 1 = 9 df and a level of significance of 0.1</u>, hence the critical value is $t^{\ast} = -1.383$ .

You can learn more about the t-distribution at brainly.com/question/26062194

5 0

3 years ago