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3 years ago

8

How do I find the indicated value for this problem?

1 answer:

Soloha48 [4]3 years ago

7 0

Answer: an = a1 +

Step-by-step explanation:

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Will mark brainliest :)

kap26 [50]

Answer: Don't know sorry

Step-by-step explanation:

3 0

3 years ago

Please help!!! Solve for the m

hjlf

Answer:

36°

Step-by-step explanation:

$m\angle C =sin^{-1}\frac{17}{29}\\m\angle C =35.888297553\degree\\m\angle C =36\degree$

4 0

3 years ago

1. Given GH = 7x + 3, HI= 3x - 5,<br> and GI= 9x + 5.<br> H<br> G<br> A. Find x:<br> B. Find GH:

blsea [12.9K]

Answer:

$\boxed{\bf x=7}$

$\boxed{\bf GH= 52}$

Step-by-step explanation:

In the line segment..

$\bf 7x+3+3x-5=9x+5$

Combine like terms.

$\bf 10x-2=9x+5$

Add -2 to both sides.

$\bf 10x-2+2=9x+5+2$

$\bf 10x=9x+7$

Subtract 9x from both sides.

$\bf 10x-9x=9x+7-9x$

$\boxed{\bf x=7}$

$\bf GH=7x+3$

$\bf 7(7)+3$

$\bf 49+3$

$\boxed{\bf 52}$

<h3>__________________</h3>

6 0

3 years ago

14. If you purchased a string of lights, how could you determine if the lights were wired in series or

BartSMP [9]

What do you think it is

3 0

3 years ago

In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of ∠K, to the nearest 10th of a degree.

Tasya [4]

Given:

In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°.

To find:

The value of ∠K to the nearest 10th of a degree.

Solution:

According to the Law of Sine:

$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$

We have, In ΔJKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°.

Using the Law of Sine, we get

$\dfrac{j}{\sin J}=\dfrac{k}{\sin K}$

$\dfrac{3.8}{\sin (63^\circ)}=\dfrac{4.1}{\sin K}$

$3.8\sin K=4.1\sin (63^\circ)$

$\sin K=\dfrac{4.1\sin (63^\circ)}{3.8}$

$\sin K=0.961349$

$K=\sin^{-1}(0.961349)$

$K=74.0182$

$K\approx 74.0$

Therefore, the measure of angle K is 74.0 degrees.

7 0

4 years ago