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3 years ago

10

PLEASE ANSWER FAST AND CORRECTLY, WORTH 74 POINTS!!!! An architect built a scale model of a sports stadium using a scale in whic

h 3 inches represents 45 feet. The height of the sports stadium is 180 feet. What is the height of the scale model in inches?

1 answer:

Marina86 [1]3 years ago

3 0

It is 12 inches long

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The length of a model car is 1/20 of the length of the actual car. If the model. is 8.7 inch long, how long is the actual car? E

madam [21]

This means that if the model is 1 in lengh then th ereal car is 20 times of that or 20 in legnth

so to find the answer, just multiply model by 20
8.7 =model
real=8.7 times 20=174
real car is 174 inches

12 inches=1 foot
conversion factor
1 ft/12in=1=convesion

so
174 times 1/12=14 and 6/12

the answer is 14 feet and 6 inches or 14.5 feet

7 0

3 years ago

Read 2 more answers

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of te triangle is 16m to the power of 2, what are the base

Olenka [21]

Answer:

The base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

Step-by-step explanation:

Given:

A triangle has a base of x 1/2 m and a height of x 3/4 m. If the area of the triangle is 16m to the power of 2.

Now, to find the base and height of the triangle.

The base of triangle = $x\times\frac{1}{2} =\frac{x}{2} \ m.$

The height of triangle = $x\times \frac{3}{4} =\frac{3x}{4}\ m.$

The area of triangle = $16\ m^2.$

Now, we put the formula of area to solve:

$Area=\frac{1}{2} \times base\times height$

$16=\frac{1}{2} \times \frac{x}{2} \times \frac{3x}{4}$

$16=\frac{3x^2}{16}$

<em>Multiplying both sides by 16 we get:</em>

<em /> $256=3x^2$ <em />

<em>Dividing both sides by 3 we get:</em>

<em /> $\frac{256}{3} =x^2$ <em />

<em>Using square root on both sides we get:</em>

$\frac{16}{\sqrt{3}}=x$

$x=\frac{16}{\sqrt{3}}$

Now, by substituting the value of $x$ to get the base and height:

$Base=\frac{x}{2}\\\\Base=\frac{\frac{16}{\sqrt{3}}}{2} \\\\Base=\frac{8}{\sqrt{3}} \ m.$

<em>So, the base of triangle = </em> $\frac{8}{\sqrt{3}} \ m.$ <em />

$Height=x\times\frac{3}{4} \\\\Height=\frac{16}{\sqrt{3}}\times \frac{3}{4} \\\\Height=\frac{12}{\sqrt{3}} \ m.$

<em>Thus, the height of triangle = </em> $\frac{12}{\sqrt{3}} \ m.$ <em />

Therefore, the base of triangle is $\frac{8}{\sqrt{3}} \ m$ and the height of triangle is $\frac{12}{\sqrt{3}} \ m.$

7 0

3 years ago

Express 5/33 as a percent. Round to the nearest tenth.

iris [78.8K]

Rounded to the nearest tenth would be 15.2%.

5 0

3 years ago

9. If 3/4 of a ton of sand covers 2/5 of a playground, how many tons of sand are required to cover the entire playground

Lynna [10]

1 7/8 tons of sand will be required to fill the playground

6 0

2 years ago

Equation practice with angle addition

Triss [41]

Answer:

36 degrees

Step-by-step explanation:

since, m<AOB is a right angle, we shall just create an equation:

M<AOB+M<BOC=90 degrees

Substitute: 6z-12+3z+30=90

Solve: 6z+3x=9z

-12+30=18

so, 9z+18=90 degrees

-18 -18

9z=72

z=8

So if z=8, then we should fit it so that it matches measure of AOB.

6z-12

6 times 8=48

48-12= 36

6 0

3 years ago