Someone please help me this is due in a few mintues ;-;

What is the solution set of -50<7k+6<-8

kirill115 [55]

Answer:

(- 8, - 2 )

Step-by-step explanation:

Given

- 50 < 7k + 6 < - 8 ( subtract 6 from each of the 3 intervals )

- 56 < 7k < - 14 ( divide all 3 intervals by 7 )

- 8 < k < - 2

Solution set is (- 8, - 2 )

8 0

4 years ago

In the figure, ∆ABD ≅ ∆CBD by Angle-Side-Angle (ASA). Which segments are congruent by CPCTC?

3241004551 [841]

AB = BC l guess this is the answer

5 0

4 years ago

Read 2 more answers

The discount on a new stereo was $180. This was a discount of 18%. What was the original selling price?

katrin2010 [14]

Answer: 180.18

Step-by-step explanation:

6 0

3 years ago

32. Parallelogram ABCD has vertices A(0,0), B(2,4), and C(10,4). Find the coordinates of D.

goblinko [34]

Answer:

The fourth vertex is D(8, 0)

Step-by-step explanation:

Let A(0, 0), B(2, 4), and C(10, 4) be the three vertices of a parallelogram ABCD and let its fourth vertex be D(a, b).

Join AC and BD. Let AC and BD intersect at point O.

We have known that the diagonals of a parallelogram bisect each other.

So, O would be the midpoint of AC as well as that of BD.

$A\left(0,\:0\right)=\left(x_1,\:x_2\:\right)$

$C\left(10,\:4\right)=\left(x_2,\:x_2\:\right)$

The midpoint of AC is:

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

$\left(x_1,\:y_1\right)=\left(0,\:0\right),\:\left(x_2,\:y_2\right)=\left(10,\:4\right)$

$=\left(\frac{10+0}{2},\:\frac{4+0}{2}\right)$

$=\left(5,\:2\right)$

The midpoint of BD is:

$=\left(\frac{a+2}{2},\:\frac{b+4}{2}\right)$

so

∵ $\frac{a+2}{2}=5$

$a+2=10$

$a=8$

∵ $\frac{b+4}{2}=2$

$b+4=4$

$b=0$

Hence, the fourth vertex is D(8, 0)

4 0

3 years ago

Can someone help me with this?

yan [13]

I'm assuming you want the total surface area.

This is a trapezoidal prism. The bases are the parallel faces running horizontal (parallel to the ground) and they are congruent trapezoids. The lateral sides are rectangles.

-------------------------------------------------

Lateral Faces:
The back face (hidden from view) is a rectangle that is 12 inches by 3 inches, so it has an area of 12*3 = 36 sq inches

The front slant faces on the left and right are each 3*5 = 15 sq inches in area

The front center lateral face has area of 6*3 = 18 sq inches

The total lateral surface area is 15+18+15+36 = 84 sq inches

-------------------------------------------------

The bases are each the same trapezoid. The trapezoid has two parallel sides of 12 and 6 inches. Call this b1 and b2. The height of the trapezoid is h = 4. Imagine the trapezoid is laid flat in a 2D perspective instead of a 3D one.

The area of one trapezoid is...
A = h*(b1+b2)/2
A = 4*(12+6)/2
A = 4*(18)/2
A = 72/2
A = 36

So the area of both base faces combined is 2*36 = 72

-------------------------------------------------

The total surface area is then found by adding the total lateral surface area (84) and the total base area (72) to get 84+72 = 156

Final Answer: 156 square inches

4 0

3 years ago