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3 years ago

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Mathematics

2 answers:

Tema [17]3 years ago

5 0

Answer:

Step-by-step explanation:

bcuz its is

miskamm [114]3 years ago

3 0

Answer:

C) 48x = 48; x = 1 in.

Step-by-step explanation:

good luck

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Two towns that are 31.5 km apart are 3 cm apart on a map. what is the scale of the map?

VLD [36.1K]

Answer:

1 cm : 10.5 km

Step-by-step explanation:

We are given that two towns are 31.5 km in real and are 3 cm apart on a map and we are to find the scale of the map.

For this, we can use the ratio method.

$\frac { 3 cm } { 1 c m } = \frac { 3 1 . 5 k m } { x }$

$x = \frac { 3 1 . 5 \times 1 } { 3 }$

$x = 1 0 . 5$

Therefore, the scale of the map would be 1 cm : 10.5 km.

8 0

3 years ago

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Lalo has 1,500 minutes per month on his cell phone plan. How many more minutes can he use if he has already talked for 785 minut

emmainna [20.7K]

Answer:

All you have to do is subtract 1500-785 in order to find the number of minutes left for him.

1500-785=715 more minutes left

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3 years ago

Which solid figure does this net represent?

ElenaW [278]

Answer:

C) triangular prism

Step-by-step explanation:

The net represents a three-dimensional shape. The figure that the net represents is a rectangular prism.

3 0

2 years ago

Read 2 more answers

G(x) = -(x - 3)2 The composite function (gºg)(x)

AlexFokin [52]

Answer:

just add or * them to get the answer

Step-by-step explanation:

8 0

3 years ago

For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

3 years ago