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nikklg [1K]
4 years ago
9

What is a number k is less than 10 as an inequality

Mathematics
1 answer:
joja [24]4 years ago
5 0
K<10; Because k is less than which means any number under 10
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2x to the third power - 4y to the second power-10
SCORPION-xisa [38]
2 (x^3 - 2y^2 -5)

hope this helps

you are trying to factor as much out as possible from each

in this case, it is 2
5 0
3 years ago
scrie patru perechi de numere naturale astfel incat diferenta numerelor din fiecare pereche sa fie 2989
ioda
Do you happen to have this in english i dont understand it at all :/
7 0
3 years ago
Please help me. I'm lost.
amm1812
Yes cause he can decrease the perimeter in any way and it would change the area and idk the other 2 in the front
6 0
3 years ago
PLEASEEEE HELPPP ITS DUE IN 15 MINUTES!! the exponential regression representing the population of Lazy Town as a function of ti
Advocard [28]

Given:

R^2=0.92,a=8000,b=0.9.

Exponential regression model is

y_1\sim a(b)^{x_1}

To find:

The exponential regression representing the population of Lazy Town as a function of time in years.

Solution:

Exponential regression model is

y_1\sim a(b)^{x_1}       ...(i)

We have, a=8000,b=0.9.

Substituting a=8000 and b=0.9 in (i), we get.

y_1\sim 8000(0.9)^{x_1}

Therefore, the exponential regression representing the population of Lazy Town as a function of time in years, is y_1\sim 8000(0.9)^{x_1}.

4 0
3 years ago
Solve the system by elimination.<br> -2x+2y+3z=0<br> -2x-y+z=-3<br> 2x+3y+3z=5
jeyben [28]

Answer:

The answer to your question is:

x = 1; y = 1, z = 0

Step-by-step explanation:

                                            -2x + 2y + 3z = 0        (I)

                                             -2x - y + z = -3           (II)

                                              2x + 3y + 3z = 5      (III)

I and II. Multiply II by 2

                                      -2x + 2y + 3z = 0

                                  (2)(-2x -   y  +   z = -3 )

                                       -2x + 2y + 3z = 0

                                       -4x -  2y  + 2z = -6

                                      -6x           + 5z = - 6       (IV)

II and III. Multiply II by 3

                                      -6x - 3y +  3z = -9     (II)

                                       2x + 3y + 3z = 5      (III)

                                     -4x         + 6z = -4           (V)

IV and V. Multiply IV by 2 and V by -3

                                   -12x  +  10z = -12

                                     12x  -  18z = 12

                                             - 8 z = 0

                                                   z = 0

Substitute z in IV

                              -6x + 5(0) = -6

                             -6x = -6

                                x = 1

Substitute x and z in I

                              -2(1) + 2y + 3(0) = 0

                              -2 + 2y = 0

                                      2y = 2

                                        y = 1

8 0
3 years ago
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