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hjlf
2 years ago
10

The amount of liquid a bottle cap can hold would most likely be measured in

Mathematics
1 answer:
vichka [17]2 years ago
3 0
The answer is: Milliliters
You might be interested in
How does the value of the 5 in 524.2 differ from the value of the 5 in 254.6??
mina [271]
In 524.2, 5 is in the hundreds place, so it stands for 500. In 254.6, 5 is in the tens place, so it stands for 50. You know what place it is in by how far to the left or right it is from the decimal point. 
4 0
3 years ago
The length of a rectangular painting is 3 inches longer than its width. If the diagonal is 15 inches long, what is the length of
vladimir2022 [97]
A^2+b^2= 15^2

b=a-3

Use substitution
a^2+(a-3)^2= 225
a^2+a^2-6a+9=225
2a^2-6a=-216
2a^2-6a+216=0

2(a^2-3a+108)
2(a-12)(a+9)

(a-12)=0
a=12
(a+9)=0
a=-9
A is -9 or 12, but since an object can't have a negative length or width, a must be 12.

Plug this value of a in.
b=(12)-3
b=9

Final answer: Length=9, width=12
8 0
3 years ago
Read 2 more answers
The population of leave town is 1-23,560 and is decreasing at a rate of 1.5%
tangare [24]

Answer: a is correct

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A.y=-x+0.5<br> B.y=-x-0.5<br> C.y=x+0.5<br> D.y=x-0.5
omeli [17]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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