Explanation:
Given mass of sugar = 1.202 g
Molar mass of the sugar ,
= 342.29 g/mol
a) Number of moles of sugar

Number of moles of sugar in 1.202 grams is 0.0035 moles
b)Moles of each element in 
In a molecular formula of sugar there are 12 carbon, 22 hydrogen and 11 oxygen atoms
Moles of an element in molecule =
number of atoms of that element in a molecular formula × number of moles of compound
Moles of carbon = 12 × 0.0035 = 0.042 moles
Similarly
Moles of hydrogen = 22 × 0.0035 = 0.077 moles
Moles of oxygen =11 × 0.0035 = 0.0385 moles
c) Number of atoms of each type in 

Number of carbon atoms =
Number of hydrogen =
Number of oxygen atoms = 
Answer:
2Mg + O₂ ⟶ 2MgO
Explanation:
Step 1. Start with the most complicated-looking formula (O₂?).
Put a 1 in front of it.
Mg + 1O₂ ⟶ MgO
Step 2. Balance O.
We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.
Mg + 1O₂ ⟶ 2MgO
Step 3. Balance Mg.
We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.
2Mg + 1O₂ ⟶ 2MgO
Every formula now has a coefficient. The equation should be balanced. Let’s check.
<u>Atom</u> <u>On the left</u> <u>On the righ</u>t
Mg 2 2
O 2 2
All atoms are balanced.
The balanced equation is
2Mg + O₂ ⟶ 2MgO
Percentage yield=(actual yield/theoretical yield) x 100%
= (45/50) x 100%
= 90%
Answer:
Mass= 2.77g
Explanation:
Applying
P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28
PV=nRT
NB
Moles(n) = m/M
PV=m/M×RT
m= PVM/RT
Substitute and Simplify
m= (2.09×1.13×28)/(0.082×291)
m= 2.77g