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Agata [3.3K]
3 years ago
12

Calculate the molarity of the two solutions.

Chemistry
1 answer:
daser333 [38]3 years ago
4 0

1. 0.33 M

2. 0.278 M

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

1. 0.350 mol of NaOH in 1.05 L of solution.

n=0.35

V=1.05 L

Molarity :

\tt M=\dfrac{0.35}{1.05}=0.33

2. 14.3 g of NaCl in 879 mL of solution.

mol NaCl(MW=58.5 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{14.3~g}{58.5~g/mol}=0.244

Molarity :

\tt M=\dfrac{0.244}{0.879~L}\\\\M=0.278

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About 21*.3 years old

Explanation:

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4 years ago
2. A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.
Snezhnost [94]

Explanation:

Given mass of sugar = 1.202 g

Molar mass of the sugar , C_{12}H_{22}O_{11} = 342.29 g/mol

a) Number of moles of sugar

\text{number of moles}=\frac{\text{given mass of sugar}}{\text{molar mass of sugar}}=\frac{1.202 g}{342.29g/mol}=0.0035 mol

Number of moles of sugar in 1.202 grams is 0.0035 moles

b)Moles of each element in C_{12}H_{22}O_{11}

In a molecular formula of sugar there are 12 carbon, 22 hydrogen and 11 oxygen atoms

Moles of an element in molecule =

number of atoms of that element in a molecular formula × number of moles of compound

Moles of carbon = 12 × 0.0035 = 0.042 moles

Similarly

Moles of hydrogen = 22  × 0.0035 = 0.077 moles

Moles of oxygen =11 × 0.0035 = 0.0385 moles

c) Number of atoms of each type in C_{12}H_{22}O_{11}

\text{Number of atoms}=\text{number of moles of that atom in a molecular formula}\times \text{Avogadro number}

Number of carbon atoms =0.042 mole\times 6.022 \times 10^{23}=2.52\times 10^{22} atoms

Number of hydrogen =0.077mole\times 6.022 \times 10^{23}=4.63\times 10^{22} atoms

Number of oxygen atoms = 0.0385 mole\times 6.022 \times 10^{23}=2.31\times 10^{22} atoms

7 0
3 years ago
Read 2 more answers
what is the balanced equation for the reaction of solid magnesium metal with oxygen gas to produce solid magnesium oxide
GaryK [48]

Answer:

2Mg + O₂ ⟶ 2MgO

Explanation:

Step 1. Start with the most complicated-looking formula (O₂?).

Put a 1 in front of it.

Mg + 1O₂ ⟶ MgO

Step 2. Balance O.

We have fixed 2 O on the left. We need 2O on the right. Put a 2 in front of MgO.

Mg + 1O₂ ⟶ 2MgO

Step 3. Balance Mg.

We have fixed 2 Mg on the right-hand side. We need 2 Mg atoms on the left. Put a 2 in front of Mg.

2Mg + 1O₂ ⟶ 2MgO

Every formula now has a coefficient. The equation should be balanced. Let’s check.

<u>Atom</u>  <u>On the left</u>  <u>On the righ</u>t

  Mg             2                  2

  O                2                  2

All atoms are balanced.

The balanced equation is

2Mg + O₂ ⟶ 2MgO

4 0
3 years ago
Determine % yield if a student obtains 45 g of product in an experiment and the theoretical amount is determined to be 50 g
Katen [24]
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8 0
4 years ago
How many grams of N2 gas are present in 1.13 L of gas at 2.09 atm and 291 K?
solong [7]

Answer:

Mass= 2.77g

Explanation:

Applying

P=2.09atm, V= 1.13L, R= 0.082, T= 291K, Mm of N2= 28

PV=nRT

NB

Moles(n) = m/M

PV=m/M×RT

m= PVM/RT

Substitute and Simplify

m= (2.09×1.13×28)/(0.082×291)

m= 2.77g

6 0
3 years ago
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