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Agata [3.3K]
2 years ago
12

Calculate the molarity of the two solutions.

Chemistry
1 answer:
daser333 [38]2 years ago
4 0

1. 0.33 M

2. 0.278 M

<h3>Further explanation</h3>

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

1. 0.350 mol of NaOH in 1.05 L of solution.

n=0.35

V=1.05 L

Molarity :

\tt M=\dfrac{0.35}{1.05}=0.33

2. 14.3 g of NaCl in 879 mL of solution.

mol NaCl(MW=58.5 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{14.3~g}{58.5~g/mol}=0.244

Molarity :

\tt M=\dfrac{0.244}{0.879~L}\\\\M=0.278

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Answer:

<h2>377 kPa</h2>

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

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P2 is the final pressure

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Since we're finding the original pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

150 kPa = 150,000 Pa

We have

P_1 =  \frac{150000 \times 166}{66}  =  \frac{24900000}{66}  \\  = 377272.72...

We have the final answer as

<h3>377 kPa</h3>

Hope this helps you

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