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kompoz [17]
4 years ago
11

PLEASE ASAP. CHM help!

Chemistry
1 answer:
vichka [17]4 years ago
6 0

Answer:

34

Explanation:

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Calculate the total amount of energy required to change 10.0 g of water from 35.0 degrees Celsius to 110. degrees Celsius.
Makovka662 [10]

Answer:

The total amount of energy required is 25,515.2 J.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

When a system absorbs (or gives up) a certain amount of heat, it can happen that:

  • experience a change in its temperature, which involves sensible heat,
  • undergoes a phase change at constant temperature, or latent heat.

To calculate the latent heat the formula is used:

Q = m. L

Where

  • Q: amount of heat
  • m: mass
  • L: latent heat

To calculate sensible heat the following formula is used:

Q = m. c. ΔT

where:

  • Q: amount of sensible heat  
  • m: body mass
  • c: specific heat of the substance
  • ΔT: temperature range

In this case, you have in the first place a heat to raise the temp of the water from 35.0 C to 100 C, where the specific heat value for water is  4.184 \frac{J}{g*C}:

q1 = m*c*(Tfinal-Tinitial)

q1 = 10.0 g *(4.184 \frac{J}{g*C})* (100 - 35.0 C) = 2719.6 J

Now you have the heat to vaporize the water, where the heat of vaporization is 2259.36 \frac{J}{g}:

q2 = m*(heat of vaporization)

q2 = 10.0 g*(2259.36 \frac{J}{g}) = 22593.6 J

Finally, you have the heat to raise temp of steam to 110 C, where the specific heat value for steam is  2.02 \frac{J}{g*C} :

q3 = m*c*(Tfinal-Tinitial)

q3 = 10.0 g*(2.02 \frac{J}{g*C})*(110-100 C) = 202 J

The total amount of energy can be calculated as:

Q= q1 + q2 + q3

Q= 2719.6 J + 22593.6 J + 202 J

Q=25,515.2 J

<u><em>The total amount of energy required is 25,515.2 J.</em></u>

5 0
3 years ago
How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?
nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 2 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the diluted solution (C₂): 0.1 M
  • Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

4 0
3 years ago
Which statement about caves and polluted groundwater is true? A. Cave rock neutralizes the pollutants in the groundwater. B. Wel
zvonat [6]
Cave rock neutralizes pollutants in groundwater.
3 0
3 years ago
MOLE TO ATOM CONVERSIONS
Advocard [28]

Answer:

Answers are given below.

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1) 0.680 moles of H₂S

0.680 mol × 6.022 × 10²³ molecules / 1mol

4.09× 10²³ molecules

2) 8.96 moles of KI

8.96 mol × 6.022 × 10²³ molecules / 1mol

53.96 × 10²³ molecules

3) 6.500 moles of KClO

6.500 mol × 6.022 × 10²³ molecules / 1mol

39.143 × 10²³ molecules

4) 0.950 moles of NaOH

0.950  mol × 6.022 × 10²³ molecules / 1mol

5.721 × 10²³ molecules

5) 4.73 moles of Na₂CO₃

4.73  mol × 6.022 × 10²³ molecules / 1mol

28.48 × 10²³ molecules

7 0
3 years ago
The metal wire in an incandescent light bulb glows when the light is switched on and stops glowing when it is switched off. This
Helen [10]
Physical change because the matter in the object is not chemically changing 
4 0
3 years ago
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