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2 years ago

What’s the answer to number 6 ty!!

Chemistry

1 answer:

cluponka [151]2 years ago

3 0

Answer:

0.00032 M

Explanation:

From the question,

Applying the for pH

pH = -log[H⁺]............... Equation 1

Where H⁺ = Hydrogen ion concentration of Hydrochloric acid

Given: pH = 3.50

Substitute into equation 1 and solve for H⁺

3.50 = -log[H⁺]

Taking the log inverse of both side,

H⁺ = 10⁻⁽³⁵/¹⁰⁾

H⁺ = 0.00032 M

Hence the H⁺ of Hydrochloric acid is 0.00032 M

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SOMEONE ANSWER?!!?!?!,!,EMERGENCY Can someone tell me the answer plz plz I’ll give you brainlist and points plz This is my final

Vera_Pavlovna [14]

Answer: Should be A)

Explanation:

the size of planets effects the amount of gravitational force each planet has, like jupiter, it has the most gravity.

6 0

2 years ago

A gas is allowed to expand from a volume of 400 ml to 2000 ml at a constant temperature. If the the initial pressure is 3 atm, c

Lostsunrise [7]

Answer:

$P_{2}) = 0.6 \; atm$

Explanation:

<u>Given the following data;</u>

Initial volume = 400 mL

Final volume = 2000 mL

Initial pressure = 3 atm

To find the final pressure P2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

$PV = K$

$P_{1}V_{1} = P_{2}V_{2}$

Substituting into the equation, we have;

$3 * 400 = P_{2}* 2000$

$1200 = 2000P_{2}$

$P_{2}) = \frac {1200}{2000}$

$P_{2}) = 0.6 \; atm$

8 0

3 years ago

If the mass of the baking soda before the reaction was 10 grams and the mass of the vinegar was 15 grams and all of the baking s

Masteriza [31]

Answer:

8.946g NaHCO₃,

14.475g H₂O,

1.025g CH₃COO⁻Na⁺,

0.500g CO₂.

Explanation:

Baking soda (NaHCO₃) reacts with vinegar (CH₃COOH 5%) producing CH₃COO⁻Na⁺, H₂O and CO₂, thus:

NaHCO₃ + CH₃COOH → CH₃COO⁻Na⁺ + H₂O + CO₂

10g of NaHCO₃ are:

10g × (1mol / 84g) = 0.119 moles NaHCO₃

Moles of CH₃COOH in 15g of vinegar are:

15g vinegar × 5% = 0.75g CH₃COOH × (1mol / 60g) = 0.0125moles CH₃ COOH

After reaction, moles of NaHCO₃ that remains are:

0.119mol - 0.0125mol = <em>0.1065 moles NaHCO₃</em>

In mass:

0.1065mol ₓ (84g / 1mol) = <em>8.946g NaHCO₃</em>

Acetic acid reacts completely producing 0.0125moles of CH₃COO⁻Na⁺, water and CO₂. In mass:

CH₃COO⁻Na⁺ = 0.0125mol ₓ (82.03g / 1mol) = <em>1.025g CH₃COO⁻Na⁺</em>

H₂O = 0.0125mol ₓ (18.01g / 1mol) = <em>0.225g H₂O</em>

CO₂ = 0.0125mol ₓ (40g / 1mol) = <em>0.500g CO₂</em>

Now, 95% of vinegar is water (Doesn't react), that is:

15g × 95% = 14.25g H₂O. Total mass of water is:

14.25g + 0.225g = <em>14.475g H₂O</em>

Total mass is:

8.946g + 14.475g H₂O + 1.025g + 0.500g ≈ 25g. The same than initial mass following law of conservation of matter.

6 0

3 years ago

45.0 g of Ca(NO3)2 are used to create a 1.3 M solution. What is the volume of the solution

Stells [14]

As we know that Molarity is given as,

M = moles / V
Solving for V,
V = moles / M ------------------(1)
Also, moles is equal to,
moles = mass / M. mass -------------(2)
puting value of moles from eq. 2 into eq. 1,
V = (mass / M.mass) / M
Putting values,
V = (45 g / 164 g/mol) / 1.3 mol/dm³

V = 0.21 dm³

6 0

3 years ago

The pressure is changed from 500 kPa to 250 kPa. What would you expect the new volume to be if the initial volume is 200 mL?

Romashka [77]

Answer:

<h3>The answer is 400 mL</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

So we have

$V_2 = \frac{500000 \times 200}{250000} = \frac{100000000}{250000} = \frac{10000}{25} \\$

We have the final answer as

Hope this helps you

4 0

3 years ago