Triangle A is an Isosceles
Triangle B is Equilateral
Triangle C is Scalene
Answer: 2
Step-by-step explanation:
<em><u>Answer</u></em><em><u> </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>opti</u></em><em><u>on</u></em><em><u> </u></em><em><u>3</u></em><em><u>r</u></em><em><u>d</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>
Step-by-step explanation:
∆FGE ~ ∆ JKL
i.e, Angle FGE = angle JKL = 63°
and angle GEF = angle KLJ = 29°
also, angle GFE = angle KJL = 88°
so, the ∆FGE ~ ∆ JKL by AA property of similarity !!
• not other options because if we take corresponding angle they are not equal
For eg. for ∆ EFG ~ ∆ JKL
the angle EFG must be equal to angle JKL to be similar !!
but they are not equal !!
so, they are not similar !!
and such ,all other options except 3rd is wrong !!
-11x² + 2x = 10
-11x² + 2x - 10 = 10 - 10
-11x² + 2x - 10 = 0
x = <u>-(2) +/- √((2)² - 4(-11)(-10))</u>
2(-11)
x = <u>-2 +/- √(4 - 440)</u>
-22
x = <u>-2 +/- √(-436)
</u> -22<u>
</u>x = <u>-2 +/- 2i√(109)
</u> -22
x = <u>-2 + 2i√(109</u>) x = <u>-2 - 2i√(109)</u>
-22 -22
x = ¹/₁₁ - ¹/₁₁i√(109) x = ¹/₁₁ + ¹/₁₁i√(109)
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Answer:
Step-by-step explanation:
The first thing that would need to be done is solving for y. This problem has already done this. The next step is to exchange y for 
That is all. This would mean that the function notation for the equation would be:
