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3 years ago

Which similarity statement expresses the relationship between the two triangles?

Mathematics

2 answers:

Dmitry_Shevchenko [17]3 years ago

7 0

Answer :-  option 3rd !!

Step-by-step explanation:

∆FGE ~ ∆ JKL

i.e, Angle FGE = angle JKL = 63°

and angle GEF = angle KLJ = 29°

also, angle GFE = angle KJL = 88°

so, the ∆FGE ~ ∆ JKL by AA property of similarity !!

• not other options because if we take corresponding angle they are not equal

For eg. for ∆ EFG ~ ∆ JKL

the angle EFG must be equal to angle JKL to be similar !!

but they are not equal !!

so, they are not similar !!

and such ,all other options except 3rd is wrong !!

Tatiana [17]3 years ago

6 0

Answer:

the similarity statement that expresses the relationship between the 2 triangles is the 3rd one.

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The expression is given as:

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Expand the expression

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Factor out 2

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Combine the radicals

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{150} + \sqrt{180}+ \sqrt{300} + \sqrt{450})$

Expand the expression

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{25 \times 6} + \sqrt{9 \times 20}+ \sqrt{100 \times 3} + \sqrt{225\times 2})$

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Expand

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Read more about simplified expressions at:

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nasty-shy [4]

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