Bill has enough money to buy one Half pound of cheeses. How much cheese will he buy?

Pls help pls help me Compare the following 2/-3, -4/5, 21/-32, -15/24

mote1985 [20]

Step-by-step explanation:

to compare them, we should all bring to the same denominator.

the lcm (lowest common multiplier) is the that denominator.

let's use the approach of the prime factors :

3 : 3

5 : 5

32 : 2×2×2×2×2

24 : 2×2×2×3

the lcm is the combination of the longest "streaks" of the prime factors.

so,

2×2×2×2×2 × 3 × 5 = 32×15 = 480

2/-3 = -2/3 = -320/480 (as 3×160 = 480)

-4/5 = -4×96 / 5×96 = -384/480 (as 5×96 = 480)

21/-32 = -21/32 = -315/480 (as 32×15 = 480)

-15/24 = -15×20 / 24×20 = -300/480 (24×20 = 480)

as

-384/480 < -320/480 < -315/480 < -300/480

we can say

-4/5 < -2/3 < -21/32 < -15/24

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11 im pretty sure....

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Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 104 eligible vot

crimeas [40]

Answer:

The probability that exactly 27 of 104 eligible voters voted is 0.057 = 5.7%.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this case, assume that 104 eligible voters aged 18-24 are randomly selected.

This means that $n = 104$ .

Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.

This means that $p = 0.22$

Mean and standard deviation:

$\mu = 104*0.22 = 22.88$

$\sigma = \sqrt{104*0.22*0.78} = 4.2245$

Probability that exactly 27 voted

By continuity continuity, 27 consists of values between 26.5 and 27.5, which means that this probability is the p-value of Z when X = 27.5 subtracted by the p-value of Z when X = 26.5.

X = 27.5

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{27.5 - 22.88}{4.2245}$