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alexira [117]
3 years ago
15

PLEASE HELP PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE​

Chemistry
2 answers:
jasenka [17]3 years ago
8 0
B the answer is letter b
Naddik [55]3 years ago
4 0
Compound mixture element
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What is the common name of CuCO3
Vikki [24]
Copper(||) carbonate 
5 0
3 years ago
Read 2 more answers
[1] b) In a local election there were 8000 registered voters. Of these 3200 voted. What was the percentage that voted? [1] <​
Alexandra [31]

Answer:

40% of registered voters voted

Explanation:

3200 out of 8000,

or :

3200 / 8000

= 0.4

0.4 x 100 = 40

40% of registered voters voted

4 0
2 years ago
Why do many people have different habits
Lady bird [3.3K]

Answer:

Explanation:

Porque la vida, nuestra vida,  está controlada de manera muy importante por nuestros hábitos, los cuales influyen, de forma, aunque inconsciente en por ejemplo: nuestra salud, productividad, seguridad económica y, como resultado, también en nuestra felicidad. En resumen, en todo y a todos  los que nos rodean.

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3 years ago
Phenolphthalein is used as a visual indicator in a strong acid-strong base titration because
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3 0
3 years ago
How much positive charge is in 0.7 kg of lithium? with each atom having 3 protons and 3 electrons. The elemental charge is 1.602
hichkok12 [17]

Explanation:

As a neutral lithium atom contains 3 protons and its elemental charge is given as 1.602 \times 10^{-19} C. Hence, we will calculate its number of moles as follows.

          Moles = \frac{mass}{\text{molar mass}}

                     = \frac{0.7 \times 1000 g}{7 g/mol}

                     = 100 mol

According to mole concept, there are 6.023 \times 10^{23} atoms present in 1 mole. So, in 100 mol we will calculate the number of atoms as follows.

        No. of atoms = 100 \times 6.023 \times 10^{23}

                               = 6.023 \times 10^{25} atoms

Since, it is given that charge on 1 atom is as follows.

                     3 \times 1.602 \times 10^{-19}C

                    = 4.806 \times 10^{-19}C

Therefore, charge present on 6.023 \times 10^{25} atoms will be calculated as follows.

    6.023 \times 10^{25} atoms \times 4.806 \times 10^{-19} C

            28.95 \times 10^{6}C

Thus, we can conclude that a positive charge of 28.95 \times 10^{6}C is in 0.7 kg of lithium.

3 0
3 years ago
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