3, 1, -1, -3, -5
-2 -2 -2 -2
a(n) = a₁ + d(n - 1)
a(n) = 3 - 2(n - 1)
a(n) = 3 - 2(n) + 2(1)
a(n) = 3 - 2n + 2
a(n) = -2n + 3 + 2
a(n) = -2n + 5
a₁₄ = -2(14) + 5
a₁₄ = -28 + 5
a₁₄ = -23
The answer is C.
7₈/7₈, 2(-2) ˣ 2(-3), 4₂ ˣ 49-1), 5(-10)/5(-12)
Add 1/7 to both sides to get 2/7m=3/14+1/7 find common denominater (14) so multipy 1/7 by 2 to get 2/14 than add that to 3/14 to get 5/14 than take 2/7 and 5/14 turn into a decimals than divide the 2/7 on both sides to get m=?
Answer:
Step-by-step explanation:
Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
Solution to the problem
Let X the random variable of interest, on this case we now that:
The probability mass function for the Binomial distribution is given as:
For this case we want this probability:
And we can use the complement rule like this:
![P(X>9) = 1-P(X \leq 8)= 1-[P(X=0) + P(X=1) +....+P(X=8)]](https://tex.z-dn.net/?f=%20P%28X%3E9%29%20%3D%201-P%28X%20%5Cleq%208%29%3D%201-%5BP%28X%3D0%29%20%2B%20P%28X%3D1%29%20%2B....%2BP%28X%3D8%29%5D%20)
And we can find the individual probabilities like this:
And in order to do the operations we can use the following excel code:
"=1-BINOM.DIST(8,25,0.3089,TRUE)"
And we got:
Answer:
Step-by-step explanation:
Triangles by definition have 3 sides. If the sides are corresponding then it is beneficial to us if they are the same length as well. If all 3 sides in one triangle are equal in length to the corresponding sides in another triangle, then the triangles are congruent by SSS (side-side-side). This is the case for us. Side EC is corresponding and congruent to side AC; side CD is corresponding and congruent to side CB; side ED is corresponding and congruent to side AB.
