Answer:
Louis has faster pitch when compared to each of their teams.
Step-by-step explanation:
We have two pitchers which we need to compare to each of their teams.
To calculate this, we will approximate the distributions to a normal distribution, and calculate the z-score, to know what proportion of players of their team fall below their score.
For Jerry, he has a speed of 86 and his team has a mean speed of 93 and standard deviation of 3.
We can calculate the z-score for Jerry speed as:
The proportion of players that are below Jerry speed is approximated by the standard normal distribution:
For Louis, his speed is 84 and his team has a mean speed of 89 and standard deviation of 3.5.
We can calculate the z-score for Jerry speed as:
The proportion of players that are below Louis speed is approximated by the standard normal distribution:
As the proportion of players of Louis team that are below Louis speed is much bigger than the proportion of players of Jerry's team that are below Jerry speed, we can say that Louis has faster pitch when compared to each of their teams.
Answer:
<h3>13.5 m/s is the right answer.</h3>
10% of 140 is 14 so just add 14 to 140
140+14=154.
Answer: All values make a true statement.
Step-by-step explanation: Since f(x) and g(x)=x, f(x)=g(x) can also be written as x=x. That is a true statement so all values of x works.
Hope this helps!
Part A:
Consider from x = -5 to x = -4, they are 1 unit apart and the difference of their outputs is given by:
-3 - (-11) = -3 + 11 = 8.
Thus, the value of the output increases by 8 units for each one unit increase in the input.
Part B:
Consider from x = -3 to x = -1, they are 2 units apart and the difference of their outputs is given by:
21 - 5 = 16.
Thus, the value of the output increases by 16 units for each two units increase in the input.
Part C:
Consider from x = 0 to x = 3, they are 3 units apart and the difference of their outputs is given by:
53 - 29 = 24.
Thus, the value of the output increases by 24 units for each three units increase in the input.
Part D:
It can be noticed that the ratio difference in the outputs to the input intervals are equal for all the given input intervals.
i.e 8 / 1 = 16 / 2 = 24 / 3.
