The force required to punch a hole 1 cm in diameter in a steel sheet is 0.176 x 10¹³ N.
<h3>What is force?</h3>
The force is defined as the shear stress or pressure applied per unit area.
F = P/A
Given is a steel sheet whose thickness t = 5mm = 5x 10⁻³ m, shearing strength P = 2.76 × 10⁸ N/m², diameter of hole d = 1cm = 1x 10⁻² m
The area to be punched A = πd xt
A = π x 1x 10⁻² x5x 10⁻³
A = 15.7 x 10⁻⁵ m²
The force required to punch a hole is
F = 2.76 × 10⁸ / 15.7 x 10⁻⁵
F = 0.176 x 10¹³ N.
Thus, the punching force is 0.176 x 10¹³ N.
Learn more about force.
brainly.com/question/21763500
#SPJ1
Answer:
Explanation:
Let v be the terminal velocity of the bar .
emf induced in the bar of length L
= B L v where B is the value of magnetic field.
current i in the circuit containing resistance R
i = induced emf / R
BLv / R
Magnetic force in upward direction in the bar
F = BiL
= BL x BLv / R
B²L²v / R
For attainment of uniform velocity
magnetic force = weight
B²L²v / R = mg
so current
i = BLv / R
Answer:
https://physicsabout.com/acceleration-and-velcoity/
Answer:
Fa=774 N
Fb=346 N
Explanation:
We will solve this problem by equating forces on each axis.
- On x-axis let forces in positive x-direction be positive and forces in negative x-direction be negative
- On y-axis let forces in positive y-direction be positive and forces in negative y-direction be negative
While towing we know that car is mot moving in y-direction so net force in y-axis must be zero
⇒∑Fy=0
⇒
⇒
⇒
Given that resultant force on car is 950N in positive x-direction
⇒∑Fx=950
⇒
⇒
⇒
⇒
⇒
⇒
⇒
Therefore approximately, Fa=774 N and Fb=346 N