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laila [671]
3 years ago
5

Ted wants to hang a wall clock on the wall by using a string. If the mass of the wall clock is 0.250 kilograms, what should be t

he tension of the string so that it can sustain the weight of the wall clock?
Physics
2 answers:
Ahat [919]3 years ago
8 0
The clock is pulling the force towards earth's center because of gravity.
That force is equal to:
F = m*g   where g is gravitational acceleration. 

We will take that g = 9.81m/s^2

Now:
F = 0.25 * 9.81 = 2.4525 N

The string needs to sustain that force, therefore minimum Force that string has to be able to sustain is:
2.4525 N
Amanda [17]3 years ago
3 0

The answer is 2.45 newtons because 1 kg = 9.8 newtons so when we use that ratio, we get around 2.45 newtons for 0.25 kg. This would be your (B) option I think.

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Identify two potential improvements to the opal extraction process and explain how these improvements could minimize harm to the
Orlov [11]

Answer

• Improving the environmental performances

• Developing Green Mining technology

Explanation

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Opal mining is currently examining environmental impacts and adopting measures that mitigate the impacts making the process less destructive to the environment.

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7 0
4 years ago
Read 2 more answers
What is uniforlmly acelerated motion and uniform motion​
steposvetlana [31]

Uniformly Accelerated motion : When a body moves along a straight line and its velocity increases by equal amounts in equal interval of time then the motion is called uniformly accelerated motion. E.g.:- Motion of a freely falling body.

Uniform Motion : When a body covers equal distances in a straight line, equal intervals of time are called uniform motion. Example: a car moving at 20km/h in a straight line. When a body covers unequal distance in equal intervals of time in a straight line is called non-uniform Example : spinning wheel.

<h3>Difference About Uniformly Accelerated motion And Uniform Motion</h3>

In Uniform Velocity Motion a body will be moving with a constant /unchanging velocity moving in a particular direction and thus acceleration will be zero whereas in Uniform accelerated motion a body will move at constant acceleration and its velocity will keep changing with time at a constant/ steady rate.

<h2>IF YOU THINK MY ANSWER IS WRONG, CHANGE IT THANK YOU. </h2>
8 0
3 years ago
NHT0015
poizon [28]

Answer:

(1) 1×10⁻⁴

Explanation:

From the question,

α = (ΔL/L)/(ΔT)............. Equation 1

Where α = linear expansivity of the metal plate, ΔL/L = Fractional change in Length, ΔT = Rise in temperature.

Given: ΔL/L = 1×10⁻⁴, ΔT = 10°C

Substitute these values into equation 1

α  = 1×10⁻⁴/10

α = 1×10⁻⁵ °C⁻¹ .

β = (ΔA/A)/ΔT................... Equation 2

Where β = Coefficient of Area expansivity, ΔA/A = Fractional change in area.

make ΔA/A the subject of the equation

ΔA/A = β×ΔT.......................... Equation 3

But,

β = 2α.......................... Equation 4

Substitute equation 4 into equation 3

ΔA/A = 2α×ΔT................ Equation 5

Given: ΔT = 5°C, α = 1×10⁻⁵ °C⁻¹

Substitute into equation 5

ΔA/A = ( 2)×(1×10⁻⁵)×(5)

ΔA/A  = 10×10⁻⁵

ΔA/A  = 1×10⁻⁴

Hence the right option is (1) 1×10⁻⁴

3 0
3 years ago
I need help with this Physics problem. I've been stuck forever:
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6 0
3 years ago
Find the magnitude of the emf induced in the rod when it is moving toward the right with a speed 7.50 m/s.
Flauer [41]

Answer:

3 volts

Explanation:

It is given that,

Magnetic field, B = 0.8 T

Length of a conducting rod, l = 50 cm = 0.5 m

Velocity of the conducting rod, v = 7.5 m/s

We need to find the magnitude of the emf induced in the rod when it is moving toward the right. When a rod is moved in a magnetic field, an emf is induced in it and it is given by :

\epsilon=Blv

Putting all the values,

\epsilon=0.8\times 0.5\times 7.5\\\\\epsilon=3\ V

So, the magnitude of the emf induced in the rod is 3 volts.

6 0
3 years ago
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