Answer:
1.3 × 10⁻¹¹ M
Explanation:
We are going to do 4 successive dilutions. In each dilution, we will apply the dilution rule.
C₁.V₁=C₂.V₂
where,
C₁ and V₁ are concentration and volume of the initial state
C₂ and V₂ are concentration and volume of the final state
<u>First dilution</u>
C₁ = 3.1 × 10⁻⁵ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

<u>Second dilution</u>
C₁ = 7.8 × 10⁻⁷ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

<u>Third dilution</u>
C₁ = 2.0 × 10⁻⁸ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

<u>Fourth dilution</u>
C₁ = 5.0 × 10⁻¹⁰ M V₁ = 1.00 mL C₂ = ? V₂ = 40.00mL

Answer:
Did the activities help you uderstand. the topic? Why?
Answer:
at 181.0
is -723.3 kJ/mol.
Explanation:
We know, 
where, T is temperature in kelvin.
Let's assume
and
does not change in the temperature range 25.0
- 181.0
.
= (273+181.0) K = 454.0 K
Hence, at 181.0
, ![\Delta G^{0}=(-795.8kJ/mol)-[(454.0 K)\times (-159.8\times 10^{-3}kJ/K.mol)]](https://tex.z-dn.net/?f=%5CDelta%20G%5E%7B0%7D%3D%28-795.8kJ%2Fmol%29-%5B%28454.0%20K%29%5Ctimes%20%28-159.8%5Ctimes%2010%5E%7B-3%7DkJ%2FK.mol%29%5D)
= -723.3 kJ/mol
Answer:
HCl conc.= 6.0mol/L
Explanation:
From the dissociation of HCl= 1 mole H+ and 1mol Cl-, which is equivalent stoichiometrically in concentration to that of 1 mol HCl,