Ask question

Ask question

All categories

2 years ago

6

If f(x)= tan^-1(2x), find lim x->2 (f(x)-f(2))/x-2

1 answer:

lara [203]2 years ago

4 0

Answer:

The value of the limit is 12.

Step-by-step explanation:

Small typing mistake, the limit is of h tending to 0.

Then

Calling the limit L

h is the common term in the numerator, then

Simplifying by h

Since h tends to 0.

You might be interested in

Complete the square to solve<br> LaTeX: 0=-x^2+4x-5<br> Also written as<br> 0= -x^2+4x-5

Feliz [49]

X=2+-(plus or minus)i

7 0

3 years ago

What is the surface area of the prism?

Sever21 [200]

Answer:

Question 3: 582 ft²

Question 4: 348 in²

Step-by-step Explanation:

Question 3:

Consider the solid shape given as being consisting of two rectangular prism. With careful examination, you'd observe that the offer one beneath has dimensions, $l, w, h, as 15, 4, 9$

The second one has $l, w, h, as 6, 4, 6$

Surface area of the bigger rectangular prism = total surface area - area of the surface that is joined to the smaller rectangular prism.

Area of the face joined to the smaller rectangular prism = 4*6 = 24 ft²

Surface area of the bigger rectangular prism = $2(wl + hl + hw) - 24$

$2(4*15 + 9*15 + 9*4) - 24$

$462 - 24$

Surface area of the bigger rectangular prism = 438 ft²

Surface area of the smaller rectangular prism = total surface area of rectangular prism - area of the surface that is joined to the bigger rectangular prism.

= $2(wl + hl + hw) - 24$

$= 2(4*6 + 6*6 + 6*4) - 24$

$= 168 - 24 = 144 ft^2$

<em><u>Surface area of the solid = 438 + 144 = 582 ft²</u></em>

Question 4:

Surface area of the triangular prism is given as: 2(B.A) + P*L

Where,

B.A = area of 1 triangular base = ½*height of the triangle*base of the traingle

B.A = ½*6*16 = 3*16 = 48 in²

P = perimeter of 1 triangular base = sum of all sides of the triangle.

P = 16+10+10 = 36 in

L = length or height of prism =

Plug in the values to find surface area of the prism

Surface area = 2(B.A) + P*L

= 2(48) + 36*7 = 96 + 252 = 348 in²

<em><u>Surface area of prism = 348 in²</u></em>

4 0

3 years ago

Is the sqrt of 1 - sin^2 theta = cos theta true? If so, in which quadrants does angle theta terminate?

Genrish500 [490]

Answer:

Answer: The answer is option B.

Step-by-step explanation:

Here,

We have,

${ \sin }^{2} theta \: + {cos}^{2}theta = 1$

${cos}^{2} \: theta = 1 - {sin}^{2} \: theta$

$cos \: theta = \sqrt{1 - { \sin }^{2}theta }$

So, it's true; and it lies in quadrant 1 and 4.

The reason according to the "CAST" rule cos theta is in 1st and 3rd quadrant cos theta is positive.

7 0

3 years ago

15 POINTS! someone pls answer

soldier1979 [14.2K]

Answer:

$2(\frac{1}{2} *20*50)+2(\frac{1}{2} *20*10)$

Step-by-step explanation:

The formula for the area of a triangle is $\frac{1}{2} *b*h$

The triangles that can be made is the triangle that has legs 20 and 50 and the triangle that has legs 20 and 10.

Since there are 2 of each triangles, we get:

$2(\frac{1}{2} *20*50)+2(\frac{1}{2} *20*10)$

The answer that fits is the first option.

3 0

3 years ago

A recipe calls for 3/4 lb of cream cheese. A small tub of cream cheese at the grocery store weighs 12oz. Is this enough cream ch

Vsevolod [243]

Yes this is enough cream cheese

4 0

3 years ago