Answer:
The degrees of freedom is 11.
The proportion in a t-distribution less than -1.4 is 0.095.
Step-by-step explanation:
The complete question is:
Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4 if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion
Solution:
The information provided is:

Compute the degrees of freedom as follows:


Thus, the degrees of freedom is 11.
Compute the proportion in a t-distribution less than -1.4 as follows:


*Use a <em>t</em>-table.
Thus, the proportion in a t-distribution less than -1.4 is 0.095.
Adjusted balance = 622.82 - 45.45 + 78.91 + 16.36 = 672.64
Adjused balance method finance charges = 672.64 x 0.1195/12 = 6.70
Average daily balance = ((622.82 x 3) + (577.37 x 6) + (656.28 x 15) + 672.64 x 6)) / 30 = (1868.46 + 3464.22 + 9844.20 + 4035.84) / 30 = 640.42
Daily balance method finance charges = 640.42 x 0.1195/12 = 6.38
Answer:
55
Step-by-step explanation:
There are 11 tens in 110, so 11 times 5 is 55.