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dybincka [34]
3 years ago
7

Someone help fast please

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

∠C ≈ 11.978°

Step-by-step explanation:

sin (∠C)/5 = sin (95°)/24

=> sin (∠C) = 5 × sin (95°) ÷ 24

=> ∠C = sin^{-1}(5 × sin (95°) ÷ 24)

=> ∠C ≈ 11.978°

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Look at Diagram.<br> It says,"<br> ST and TU are tangent to Q. What is the value of x?"
shutvik [7]

Answer:x=18

Step-by-step explanation:2x-9=x+9

3 0
4 years ago
How many 0.4 liter glasses of water are contained in a 5.2 - liter pitcher? How do you find it out step by step?
Novay_Z [31]
Let's start out with what we do know:
We have a 5.2L pitcher and 0.4L glasses and we want to know how many glasses we can fill with the 5.2L pitcher of water.

To answer that, we need to divide 5.2L by 0.4L in order to get the number of glasses (the number of 0.4L glasses that can go into a 5.2L pitcher)

So our equation will look like this:

n = \frac{5.2L}{0.4L} where n = number of glasses
so by doing that division we get:

n = 13
Notice that the L's cancel out leaving us with a plain number.

So a 5.2L pitcher of water can fill up 13 glasses!
7 0
3 years ago
NO LINKS!!!!!
8090 [49]

9514 1404 393

Answer:

  5x^2 +10x = -5

Step-by-step explanation:

The equation will have one solution when the discriminant is zero.

In standard form, the equation is ...

  ax^2 +10x -c = 0

The discriminant of the equation ax^2+bx+c=0 is  ...

  b^2 -4ac

so the discriminant of your equation is ...

  10^2 -4a(-c) = 100 +4ac

We want that to be zero, so we require ...

  100 +4ac = 0

  25 +ac = 0

  ac = -25

Any pair of values of 'a' and 'c' that have a product of -25 will satisfy the requirement. As you state, one possible pair is a = 5 and c = -5. Putting these values into the given equation makes it ...

  5x^2 +10x = -5 . . . . . the equation with a=5, c=-5

_____

<em>Additional comment</em>

Your problem statement does not require that 'a' be non-zero. If <em>a=0</em>, then the equation will have one real solution for <em>any value of c</em>.

If you restrict the solutions to integers, then possibilities include ...

  (a, c) = (1, -25), (5, -5), (25, -1), (-25, 1), (-5, 5), (-1, 25)

6 0
3 years ago
Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%
balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

4 0
2 years ago
A group of eight people are attending the movies together.
sveta [45]

Answer:

I think A

Step-by-step explanation:

4 0
3 years ago
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