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saul85 [17]
3 years ago
8

Please I just need a simple explanation for this I will mark brainliest!!!!

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

Angle ACB = Angle YZX

In the reasoning SSS, u need 3 corresponding sides, and in this proof, u are given 2 sides and an angle, so technically the reason is SAS.

stiv31 [10]3 years ago
4 0

Angle ACB = Angle YZX

is the correct answer to the question

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Current rules for telephone area codes allow the use of digits​ 2-9 for the first​ digit, and​ 0-9 for the second and third​ dig
Anna35 [415]

Using the fundamental counting theorem, we have that:

  • 648 different area codes are possible with this rule.
  • There are 6,480,000,000 possible 10-digit phone numbers.
  • The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.

For the area code:

  • 8 options for the first digit.
  • 9 options for the second and third.

Thus:

8 \times 9 \times 9 = 648

648 different area codes are possible with this rule.

For the number of 10-digit phone numbers:

  • 7 digits, each with 10 options.
  • 648 different area codes.

Then

648 \times 10^7 = 6,480,000,000


There are 6,480,000,000 possible 10-digit phone numbers.

The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.

A similar problem is given at brainly.com/question/24067651

5 0
3 years ago
How do u do this what’s the answer?
Kobotan [32]
Okay! the answer is 24.
7 0
4 years ago
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Figure ABCD is a parallelogram.
bogdanovich [222]
A = C (congruent angles)

Then: 4p+12 = 36

Solve for p

4p = 36 - 12

4p = 24

4p/4 = 24/4

p = 6

Answer is going to be A.
6 0
3 years ago
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How do i solve 2x-y=9
devlian [24]
20 with a number minus what will equal 9. ^_^
3 0
4 years ago
I am ab to ask the HARDEST question in history... you ready?
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0? I honestly had to think about this cause I’m so tired but tryna help folks lol
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3 years ago
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