1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sladkaya [172]
3 years ago
11

8.1 as a mixed number​

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

8 1/10 as a mixed number sorry if I'm wronge

You might be interested in
The tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm2 and a stand
Elanso [62]

Answer:

95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

Yes, this data suggest that the tensile strength was changed after the adjustment.

Step-by-step explanation:

We are given that the tensile strength of stainless steel produced by a plant has been stable for a long time with a mean of 72 kg/mm 2 and a standard deviation of 2.15.

A machine was recently adjusted and a sample of 50 items were taken to determine if the mean tensile strength has changed. The mean of this sample is 74.28. Assume that the standard deviation did not change because of the adjustment to the machine.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                         P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean strength of 50 items = 74.28

            \sigma = population standard deviation = 2.15

            n = sample of items = 50

            \mu = population mean tensile strength after machine was adjusted

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                  significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                 = [ 74.28-1.96 \times {\frac{2.15}{\sqrt{50} } } , 74.28+1.96 \times {\frac{2.15}{\sqrt{50} } } ]

                 = [73.68 kg/mm2 , 74.88 kg/mm2]

Therefore, 95% confidence interval for the mean of tensile strength after the machine was adjusted is [73.68 kg/mm2 , 74.88 kg/mm2].

<em>Yes, this data suggest that the tensile strength was changed after the adjustment as earlier the mean tensile strength was 72 kg/mm2 and now the mean strength lies between 73.68 kg/mm2 and 74.88 kg/mm2 after adjustment.</em>

8 0
3 years ago
Solve the equation for x.<br> 2(x-2) + 6 = 2
Tpy6a [65]

Answer:

x=0

Step-by-step explanation:

2x-4+6=2

2x+2=2

2x=0

x=0

6 0
3 years ago
Read 2 more answers
HELP ASAP!!
garri49 [273]
I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.

</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct

</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct

</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>
4 0
3 years ago
The Ford family decides they want to go see a movie at the local movie theater. The family consists of two adults, and five chil
Brrunno [24]

Ford Family consists of:

a) 2 adults

The price of ticket for each adult is $18.55. This can be approximated to $19 if we round it to nearest dollar. So the price of ticket for 2 adults will be 2 x 19 = $38

b) 3 children between ages 2 and 10.

Ticket for each child between ages 2 - 10 is $12.59 which can be approximated to $13. So ticket price for 3 children will be 3 x 13 = $39

c) 2 children below the age of 2.

Ticket price for each child is $6.54 which can approximated as $7. So ticket price for 2 children will be 2 x 7 = $14

The estimated total amount due on the family equals = 38 + 39 + 14 = $91

In each of the 3 cases we rounded up the values. So this means the actual amount must be slightly lesser than $91. The actual bill was $87.95 which is close to $91 and lesser than it. Hence we can conclude that $87.95 is the correct amount due for Ford Family.

3 0
3 years ago
What is 2 plus 2
kotegsom [21]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Other questions:
  • A rectangle has a length of 6 cm and a width of 3 cm. Each side is doubled in length. What is the ratio of the areas of the two
    12·2 answers
  • Complete the square to determine the maximum or minimum value of the function defined by the expression. x2 + 30x + 21 A) maximu
    9·2 answers
  • A car is traveling up a steep ramp to a parking garage.the ramp is 445 feet long and rises a vertical distance of 80 feet. What
    9·2 answers
  • What is 2.7 repeating as a fraction?
    15·2 answers
  • Someone PLEASE help
    5·2 answers
  • Factor the polynomial 3x^2 + 15x + 18
    11·1 answer
  • The marked price of a radio is Sh. 12600. If the shopkeeper can allow a discount of 15% on the marked price and still make a pro
    13·1 answer
  • Change 3.7 hours into hours and minutes
    5·1 answer
  • 15.12 for 12 hamburgers per burger
    14·1 answer
  • What do you get when you combine the following numbers? -4-4-4-4
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!