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Sladkaya [172]
3 years ago
11

8.1 as a mixed number​

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

8 1/10 as a mixed number sorry if I'm wronge

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Pleassssseee heelelllppp
alexgriva [62]

Answer:

Ten Peaches and five bananas.

Step-by-step explanation

To solve the problem increase the cost by adding more peaches and less by adding more bananas

7 peaches = 3.50

8 bananas = 3.20 + 3.50 = 6.70

We need 30 more cents so add three more peaches

10 peaches = 5

5 x 0.4 = 2

2 + 5 = 7

5 0
3 years ago
he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w
stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666   )

Step-by-step explanation:

Given the data in the question;

Sample 1                                Sample 2

x"₁ = 259.23                            x"₂ = 365.12

s₁  = 34.713                              s₂ = 48.297

n₁ = 5                                       n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

S_p^2 = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

S_p^2 = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

S_p^2 = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [  4 + 9 ]

S_p^2 = [ 4819.9692 + 20993.4 ] / [  13 ]

S_p^2 = 25813.3692 / 13

S_p^2 = 1985.64378

Now the Standard Error will be;

S_{x1-x2 = √[ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

S_{x1-x2 = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

S_{x1-x2 = √[ 397.128756 + 198.564378 ]

S_{x1-x2 = √595.693134

S_{x1-x2 = 24.4068

Critical Value = t_{\frac{\alpha }{2}, df = t_{0.05, df=13 = 1.771  { t-table }

So,

Margin of Error E =  t_{\frac{\alpha }{2}, df × [ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666   )

3 0
3 years ago
Round each addendum to the nearest ten. 478 + 112
Amiraneli [1.4K]
500 and 100 because if you see the seven right, seven is the judge and so as the one. Make it 500 and the next number 100. So you'll have en estimate of 600. Ur welcome.
8 0
3 years ago
Which of the following terms are like terms 17j3, 92m, 32j2, 12j, 10m2, 42j, 18j3, and 6m4? Choose all answers that are correct.
zhenek [66]
A. 12j and 42j
C. 17j³ + 18j³
This is because the variables and their powers are the same in these terms
4 0
3 years ago
Read 2 more answers
According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 –
SVETLANKA909090 [29]

We have to identify the function which has the same set of potential rational roots as the function g(x)= 3x^5-2x^4+9x^3-x^2+12.

Firstly, we will find the rational roots of the given function.

Let 'p' be the factors of 12

So, p= \pm 1, \pm 2, \pm 3, \pm 4, \pm 6

Let 'q' be the factors of 3

So, q=\pm 1, \pm 3

So, the rational roots are given by \frac{p}{q} which are as:

\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{4}{3}.

Consider the first function given in part A.

f(x) = 3x^5-2x^4-9x^3+x^2-12

Here also, Let 'p' be the factors of 12

So, p= \pm 1, \pm 2, \pm 3, \pm 4, \pm 6

Let 'q' be the factors of 3

So, q=\pm 1, \pm 3

So, the rational roots are given by \frac{p}{q} which are as:

\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{4}{3}.

Therefore, this equation has same rational roots of the given function.

Option A is the correct answer.

4 0
3 years ago
Read 2 more answers
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