Answer:
The answer is x²-9x+16
Step-by-step explanation:
Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:26 Minutes
Step-by-step explanation:
5/25 = 13 13 times 2 equals 26
Answer:
8x2-30x+27 has one root (9/4) the square of the other (3/2)
Step-by-step explanation:
8x2+30x+27 = (2*x+3)*(4*x+9) => solution = {-3/2, -4/9}
One is not the square of the other because squares are positive.
8x2-30x+27 = (2*x-3)*(4*x-9) =>
solution = {3/2, 4/9} since (4/9 = (3/2)^2, therefore the preceding question is correct.
Answer: A
Step-by-step explanation:
because i did a quiz with the same and i got it right
