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ella [17]
3 years ago
9

What does the slope of a speed vs.time graph represent​

Biology
1 answer:
9966 [12]3 years ago
7 0

Answer:

It represents an acceleration.

Explanation:

The sloping line shows that the speed of the object is changing. The object is either speeding up or slowing down. If the line slopes upward from left to right, this means the object is speeding up.

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Which organelle is labeled I? cell membrane ribosome endoplasmic reticulum nucleus
Dvinal [7]

Answer:

"nucleus" seems to be the correct answer.

Explanation:

  • The nucleus seems to be a significant case wrapped through a double membrane that distinguishes these from the cytoplasm, the nuclear shell. The membranes combine throughout a few areas, allowing the interchange of substances between some of the cytoplasm as well as the nucleus, steps given designated "nuclear pores".
  • The nuclear shell is consistent with either the concentrated endoplasmic reticulum, thereby bonding with either the nucleus.
7 0
4 years ago
What are the four kingdoms that living things are classified in?
Musya8 [376]

Answer:

Protista, Fungi, Plantae, and Animalia

Explanation:

7 0
4 years ago
Joyce and Linda are identical twins who are 50 years old and enjoy exercising daily. Joyce avoids eating any dairy or animal pro
solniwko [45]

Answer:

Linda has a higher level of "bad" cholesterol than Joyce.

Explanation:

bad cholesterol is in lots of fatty and dairy food such as meat,in this case pork, and butter.

5 0
3 years ago
Read 2 more answers
Rosa drew a diagram to compare substitution mutation and insertion mutations. What label belongs in the area marked "Y"?
Bezzdna [24]

Answer:

Hey There!

_____________________________________

Answer:

_____________________________________

Mutations:

Mutations are the changes produced in the nucleotide sequence of the genome.

There are four main types of mutations

Substitution

Insertion

Deletion

Duplication.

_____________________________________

DELETION:

A small segment of chromosome mat be missing. This condition is known as deletion.

For example, Normal chromosome has A B C D E F G. If deletion mutation occurs then mutated chromosome has A D E F G and B C got deleted.

_____________________________________

DUPLICATION:

In this condition, a part of chromosome present in exec ess to the normal chromosome.

For example, Normal Chromosome has A B C D E F G. If duplication mutation occurs, then mutated chromosome had A B C B C D E F G and B C is duplicated.

_____________________________________

SUBSTITUTION MUTATION:

Substitution is a type of mutation where one base pair is replaced by a different base pair.

For example, in the sequence CAAGT, if C replaces G, it is a substitution mutation.

INSERTION MUTATION:

In genetics, an insertion is the addition of one or more nucleotide base pairs into a DNA sequence.

For example, in the sequence CAAGT, if extra base G gets inserted after C, the new sequence would be CGAAGT.

_____________________________________

Both substitution and insertion mutations change the position of nucleotide thus, the type of amino acid. Option A is correct because B and D are wrong as increase in number of bases and decrease in number of bases is because of deletion and duplication mutations here it asks for substitution and insertion mutations. C is wrong as In mutation there is always a change in bases or chromosome. So all the other choices seem incorrect as it is asking for substitution and insertion the base pair changes which results in the change in type of amino acid.

_____________________________________

Best Regards,

8 0
3 years ago
A fossil is discovered that has only 12.5% of the carbon-14 that it would have had originally (when the animal was alive). If th
mariarad [96]

Answer:

The fossil is 17,100 years old.

Explanation:

The decay equation:

\frac{dN}{dt}\propto -N

\Rightarrow \frac{dN}{dt}= -\lambda N

\Rightarrow \frac{dN}{N}= -\lambda dt

Integrating both sides

\Rightarrow \int\frac{dN}{N}= \int-\lambda dt

\Rightarrow ln |N|=-\lambda t+c

When t=0, N=N_0 = initial amount

ln |N_0|=-\lambda .0+c

\Rightarrow ln |N_0|=c

\therefore ln |N|=-\lambda t+ln|N_0|

\Rightarrow ln |N|-ln|N_0|=-\lambda t

\Rightarrow ln |\frac {N}{N_0}|=-\lambda t

\Rightarrow \frac {N}{N_0}=e^{-\lambda t}

\Rightarrow N=N_0e^{-\lambda t}

The decay equation is

N=N_0e^{-\lambda t}

Given that,

The half life of carbon - 14 is 5700 years.

For half life, N=\frac{1}{2} N_0

To find the value of  \lambda, we need to put the value of N and t in the decay equation.

\frac12N_0=N_0e^{-\lambda \times 5700}

\Rightarrow \frac12=e^{-\lambda \times 5700}             [ Divided N_0 both sides]

Taking ln both sides

\Rightarrow ln| \frac12|=ln|e^{-\lambda \times 5700}|

\Rightarrow ln| \frac12|={-\lambda \times 5700}

\Rightarrow \lambda= \frac{ln| \frac12|}{-5700}

\Rightarrow \lambda= \frac{ln|1|-ln|2|}{-5700}             [ ln|\frac mn|= ln |m|-ln |n|]

\Rightarrow \lambda= \frac{ln|2|}{5700}                      [ln 1= 0]

The fossil has only 12.5% of the carbon carbon-14 that it would have had originally.

So, N=\frac{12.5}{100} N_0

Then,

\frac{12.5}{100} N_0=N_0e^{-\frac{ln|2|}{5700}t

\Rightarrow \frac{12.5}{100} =e^{-\frac{ln|2|}{5700}t

Taking ln both sides

\Rightarrow ln|\frac{12.5}{100} |=ln|e^{-\frac{ln|2|}{5700}t}|

\Rightarrow ln|\frac{12.5}{100} |={-\frac{ln|2|}{5700}t}

\Rightarrow t=\frac{ ln|\frac{12.5}{100}|} {-\frac{ln|2|}{5700}}

\Rightarrow t=\frac{ ln|\frac{12.5}{100}|\times 5700} {-{ln|2|}}

\Rightarrow t=17,100

The fossil is 17,100 years old.

7 0
4 years ago
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