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2 years ago

Which of the following expressions is equivalent to -4(3x-5

Mathematics

1 answer:

Firdavs [7]2 years ago

5 0

-4(3x-5)

-12x+20

Please vote my answer brainliest!

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A’B’C’ is a dilation image if ABC which is the correct description of the dilation

Sav [38]

Answer:

The dilation is an enlargement

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is equal and this ratio is called the scale factor

In this problem Triangles A'B'C' and ABC are similar by AA Similarity Postulate

Let

z------> the scale factor

$z=\frac{A'C'}{AC}$

substitute the values

$z=\frac{2+8}{2}$

$z=\frac{10}{2}=5$

The scale factor is greater than 1

therefore

The dilation is an enlargement

3 0

2 years ago

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A playground is shaped like a rectangle with a width 5 times it’s length. What is the simplified expression for the distance bet

Bad White [126]

Width: W
length: L = 5W

Use the Pyth. Theorem to find the length of the diagonal:

|D| = sqrt(W^2 + [5W]^2) = sqrt(W^2 + 25W^2) = sqrt(26W^2), or

Wsqrt(26) (ans.)

8 0

2 years ago

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A group of 52 people attend a ball game. There were three times as many men as women in the group. Write and solve a system of e

kkurt [141]

Answer:

lets call the children, c, and call adult, a,

c+a= 52 eq 1: a=52-c

c=3a eq 2

take a's value from eq 1 and plug it into eq 2

c=3(52-c)

c=156-3c

4c=156

c=39 the number of children that attended the ball game.

Step-by-step explanation:

3 0

2 years ago

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Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

2 years ago

Need help answering<br><br> Will give brainliest to whoever is correct first

Setler [38]

The answer is 5. Measure r and t are congruent. Measure r is 20 so measure t is also 20. So by dividing 20 by 4 you get 5.

5 0

2 years ago