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3 years ago

Describe how to find the sale price of an item that has been discounted 15%.

Mathematics

1 answer:

Liula [17]3 years ago

5 0

Answer:

Make me op

Step-by-step explanation:

The rate is usually given as a percent.

To find the discount, multiply the rate by the original price.

To find the sale price, subtract the discount from original price.

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Please show steps in solving: B/3 + B/4 + B/6 =

alexandr1967 [171]

Answer:

= 3b/4

Step-by-step explanation:

= b . 4/12 + b . 3/12 + b . 2/12

Apply the fraction rule: a/c + b/c = a + b/c

= b . 4 + b . 3 + b . 2/12

= 4b + 3b + 2b/12

Add similar elements: 4b + 3b + 2b = 9b

= 9b/12

Cancel 9b/12: 3b/4

= 3b/4

5 0

3 years ago

Which shows the expressions rewritten with the least common denominator?

baherus [9]

Answer:

D. (14x-4)/(8x^2) and (x^2-x)/(8x^2)

Step-by-step explanation:

The least common denominator will be 8x^2, the product of 2 and x to the highest of their powers in either of the denominators.

$\left\{\dfrac{7x-2}{4x^2},\ \dfrac{x-1}{8x}\right\}=\left\{\dfrac{7x-2}{4x^2}\cdot\dfrac{2}{2},\ \dfrac{x-1}{8x}\cdot\dfrac{x}{x}\right\}\\\\=\left\{\dfrac{14x-4}{8x^2},\ \dfrac{x^2-x}{8x^2}\right\}$

7 0

2 years ago

[im posting this for YALLS benefit- don’t make the same mistake i did besties <33

Anestetic [448]

Answer:

false

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago

If you dont know the answer to my question then dont say anything!

umka2103 [35]

Answer:

False

Step-by-step explanation:

You can't rely slowly upon induction to prove that your conclusion us correct.

4 0

3 years ago

Read 2 more answers