1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Travka [436]
3 years ago
14

Describe how to find the sale price of an item that has been discounted 15%.

Mathematics
1 answer:
Liula [17]3 years ago
5 0

Answer:

Make me op

Step-by-step explanation:

The rate is usually given as a percent.

To find the discount, multiply the rate by the original price.

To find the sale price, subtract the discount from original price.

You might be interested in
Camilla makes and sells jewelry. She has 8,160 silver beads and 2,880 black beads to make necklaces. Each necklace will contain
Katarina [22]
8,160 ÷ 85 = <span>96

2,880 </span>÷ 30 =  96

SO, Camilla can make 96 necklaces.

Hope I helped:P
5 0
3 years ago
Read 2 more answers
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
3 years ago
Anacondas are snakes found in South America anacondas can measure over 16 1/2 feet in length how many inches are in 16 1/2
OLga [1]

Answer:

198 inches

Step-by-step explanation:

There are 12 inches in each foot

multiply 16 by 12 you get 192

Half of a foot is 6 inches

add 6 inches and you get 198

5 0
3 years ago
Read 2 more answers
A customer ordered a product online for $299 and was charged an additional $10 for shipping and handling. The customer received
swat32

Answer:

$192.4

Step-by-step explanation:

First, we'll work out what the customer had to pay before tax.

That's

299+10-99-25\\=185(USD)

4% of 185 is 7.4,

So the customer paid

185+7.4\\=192.4(USD)

6 0
2 years ago
Help on this math question. 25 points.
solniwko [45]

Answer:

the third one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • How can i find the x and y intercepts of a graph equation? (ex. y+ x-4)
    7·1 answer
  • Greatest common factor of the following monomials 34c^3 and 2c^5
    6·1 answer
  • Math Question, please help! Please show your work so I know how you got your answer and thanks in advance! :)
    13·1 answer
  • What is it? Eighty-six divided by six??
    10·2 answers
  • Whut is 2 pus 2 i dount no
    7·1 answer
  • Solve X^2 + 5x + 6 = 0
    10·2 answers
  • Write the polynomial function of least degree that has zeros of x=-i and x=1​
    15·1 answer
  • Ailey is shopping at a department store during a 20% off everything sale. She also has a coupon for $5.00 off the sale amount. H
    14·1 answer
  • Please help me with this thanks
    6·1 answer
  • Please help me. right answer will get brainliest
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!