3)The original rational number was 17/12.
4)The age of Ruby and Reshma are 20 and 28 years respectively.
Explanation:
3)Let the numerator be x.
So denominator will be (x - 5)
If we add 5 to numberator then it will be (x + 5)
New number is (x + 5)/(x - 5)=11/6
Solve for X by cross multiplying
6(x + 5)=11(x - 5)
6x + 30=11x - 55
5x=85
x=17
So original rational number was 17/12.
4)The ages of Ruby and Reshma are in the ratio 5:7
So, let the present ages of Ruby and Reshma be 5x and 7x respectively.
Also, it is given that four years from now the ratio of their ages will be 3:4
So, the equation - 5x + 4 / 7x + 3 = 3/4
⇒4(5x+4)=3(7x+4)
⇒20x+16=21x+12
⇒21x−20x=16−12
⇒x=4
⇒5x=20 and 7x=28
The age of Ruby and Reshma are 20 and 28 years respectively.
The formula for fractional exponents is
![\sqrt[n]{m} = x^{ \frac{m}{n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bm%7D%20%3D%20%20x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%20)
For this particular problem the expression would be written as
![\sqrt[2]{ x^{3} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7B%20x%5E%7B3%7D%20%7D%20)
Answer:
Probability at least one car will get punctured: 0.39347
Step-by-step explanation:
B(10,000 , 0.00005)
P(X ≥ 1) = 1 - P(X = 0)
= 1 - (1 - 0.00005)^10,000
= 1 - (0.99995)^10,000
= 1 - 0.60652...
= 0.39347 (probability that at least one car will get punctured)
As you can tell P(X ≥ 1) as we have to solve for the probability that at least one car will get punctured. That is of course 1 - [ P(X = 0) ].
Step-by-step explanation:
Disculpe pero de qué grado es usted para ayudarle un poquito más mejor
