Question

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Answer 1

#1

$\\ \rm\Rrightarrow \dfrac{WX}{UV}=\dfrac{HI}{FE}$

$\\ \rm\Rrightarrow \dfrac{WX}{16}=\dfrac{10}{8}$

$\\ \rm\Rrightarrow WX/2=10$

$\\ \rm\Rrightarrow WX=20$

Again

#2

$\\ \rm\Rrightarrow \dfrac{WX}{UT}=\dfrac{HI}{FG}$

$\\ \rm\Rrightarrow \dfrac{20}{20}=\dfrac{10}{FG}$

$\\ \rm\Rrightarrow FG=10$

Answer 2

Answer:

WX = 20

FG = 10

Step-by-step explanation:

If EFGHI ~ VUTXW

then:

• EF~VU
• FG~UT
• GH~TX
• HI~XW
• IE~WV

The only pair of sides that both have measures is EF and VU

EF = 8

VU = 16

VU/EF = 16/8 = 2

Therefore, VUTXW is enlargement of EFGHI by a scale factor of 2.

As HI = 10

⇒ WX = 10 × 2 = 20

As UT = 20

⇒ FG = 20 ÷ 2 = 10