Answer:
Between 38.42 and 49.1.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 43.76, standard deviation of 2.67.
Between what two values will approximately 95% of the amounts be?
By the Empirical Rule, within 2 standard deviations of the mean. So
43.76 - 2*2.67 = 38.42
43.76 + 2*2.67 = 49.1
Between 38.42 and 49.1.
Answer: 53/5, 101/20
Step-by-step explanation:
10.6 is = 106/10. Then divide both numerator and denominator by 2. Then it equals 53/5.
5.05 = 505/100. Then divide both numerator and denominator by 5. This will equal 101/20.
Answer:
Step-by-step explanation:
N(106,14²)
(calculated using excel, let me know if you were supposed to use a normal table) = 0.4715
85.34
Q1:96.56
Q3:115.44
IQR (which is Q3-Q1)= 115.44-96.56= 18.88
Answer:
Since the diameter of the pool is 10 feet, the radius will be one-half of the diameter.
The radius will be 5 feet.
The circumference of the pool will be Pi times the diameter.
The circumference will be Pi (3.14) times 10 feet.
The circumference will be 31.4 feet.
310 - 220 = 90
90/310 = x/100 (cross multiplication)
9000 = 310x
9000/310 = x
x = around 29%