If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?
1 answer:
Answer:
width= x-7
Step-by-step explanation:
l= 8x
Area = l*b
b= 8x^2-56x/8x
b= 8x(x-7)/8x
b= x-7
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14-x=9
14=x+9
x=14-9
x=5
14+5=19
x+y=19
x-y=(-5)
Adding both equations,
We get,
x+y=19
x-y=(-5)
2x=14
x=7
x+y=19
7+y=19
y=12
Go on safari , && go to a circumference calculator , ion wanna explain rn .
Answer:
b
Step-by-step explanation:
In a calculator you would take 82 * 0.63 which equals 51.66
