3 years ago

If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?

Mathematics

1 answer:

Irina18 [472]3 years ago

7 0

Answer:

width= x-7

Step-by-step explanation:

l= 8x

Area = l*b

b= 8x^2-56x/8x

b= 8x(x-7)/8x

b= x-7

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If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?​

If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?