Answer:
Descriptives is the correct answer of this question.
Explanation:
Some software packages provide data column definitions that include qualitative summaries such as control averages, mean, average, minimum, standard deviation, number of zero values, number of empty records, etc.
- A descriptives summary is a sentence that gives someone information or something.
- Description is the style of narration creation aimed at making a location, an event, a character or a community vivid.
There are 2 types of Descriptives :-
- Narrative type.
- Argumentative type.
Answer:
Only
Option: void f1(float array[], int size);
is valid.
Explanation:
To pass an array as argument in a function, the syntax should be as follows:
functionName (type arrayName[ ] )
We can't place the size of the array inside the array bracket (arrayName[100]) as this will give a syntax error. The empty bracket [] is required to tell the program that the value that passed as the argument is an array and differentiate it from other type of value.
Answer:
D. a studio monitor
Explanation:
A studio monitor is an electrical equipment that is used to enhance the quality of sound or music. It work like a speaker that can be used professionals to record audio songs, to make films and some other applications with good quality. It is usually used in studios where producer must ensures that the quality of music. As in music industry the quality of music depends on the quality of instrument used for the purpose of recording.
<em>This is the reason that, Jimmy and his friends should choose a Studio Monitor to achieve the most accurate sound quality.</em>
Answer:
Select the slide that you want to insert a table on.On the Insert tab, in the Tables group, click Table, and then click Excel Spreadsheet.To add text to a table cell, click the cell, and then enter your text
Explanation:
Answer:
Explanation:
The code for the given problem is written below
.data
A : .word 1 2 3 4 5 6 7 8 9 10
.text
la $s5,A
li $s1,0 # load g
li $s2,10 # load h
li $s3,0 # load i
li $s4,1 # load j
loop:
mul $s6,$s3,4
add $s6,$s6,$s5 #address of A[i]
lw $s6,($s6) #get value of A[i] in s3
add $s1,$s1,$s6 #g = g+A[i]
add $s3,$s3,$s4 # i = i+j
bne $s3,$s2,loop #if i!=h jump to loop
