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3 years ago

3 1/2 as a single fraction

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

3/2 im oretty sure thats the answer

Juliette [100K]3 years ago

3 0

Answer:

7/2

3 as a whole number = 6/2

6/2 + 1/2 = 7/2

Step-by-step explanation:

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Help meh pls (problem below)

Masja [62]

Answer:

44 hours

Step-by-step explanation:

Topic of this question: Creating and Solving Equations, Rates, and Proportions

<h2>Method 1: Creating and Solving Equations</h2>

Step 1: Find the amount drilled per hour

To do this, we have to divide the amount drilled by the number of hours it took to drill and find how much is being drilled per hour.

(I know it's a mouthful)

-72ft = 24x, where x is the amount drilled per hour

-72ft ÷ 24 = x

-3ft = x

-3ft per hour

Step 2: Find how many hours it takes to drill to -132 ft

Since we know the rate of drilling per hour, we can divide the target amount by the amount drilled per hour

-132 ÷ -3 = y, where y is the number of hours it takes

44 = y

y = 44

It will take a total of 44 hours to drill to -132 ft

<h2>Method 2: Proportions</h2>

We can set up a proportion like this, where we know that it takes 24 hours to drill 72 ft, but we don't know how long it takes to drill 132 feet

$\frac{-72}{24} = \frac{-132}x$

Cross multiply

$-72x = 24 * -132$

Simplify

$-72x = -3168\\$

Divide both sides by -72

$x = -3,168/-72$

$x = 44$

It will take a total of 44 hours to dig to -132 ft

-Chetan K

8 0

3 years ago

Read 2 more answers

-3(2n+1)+7=-5 what is the value of n? Please don't forget the negatives! Thank you!

algol [13]

N=1.5 or -9/-6 start by distributing the -3 and then you want to seclude n by itself in order to solve for it

7 0

4 years ago

A random variable X is generated as follows. We flip a coin. With probability p , the result is Heads, and then X is generated a

Citrus2011 [14]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

For point a:

$fx|H(x) = 1;0< x$

$=P(H)fX|H(x)+P(T)fX|T(x)\\\\= p(1) + (1-p)2x\\\\= p(1 -2x)+2x\\\\$

Using the PDF of the X value

$fX(x) =2x +p(1 - 2x); \ 0\leq x\leq 1$

0 ; otherwise

For point b:

$E(X)=\int^{1}_{0} \ x fX (x)\ dx=\int^{1}_{0} \ x(2x+p(1-2x))\ dx\\\\=\int^{1}_{0} \ (2x^2+(x-2x^2)p) dx\\\\$

$= 2(\frac{x^3}{3}) + (\frac{x^2}{2}-2(\frac{x^3}{3}) \begin{vmatrix} x=1\\ x=0\end{vmatrix} \\\\$

$= \frac{2}{3} + (\frac{1}{2} - \frac{2}{3})p\\\\= \frac{2}{3} -\frac{p}{6}\\\\= \frac{(4 - p)}{6}$

6 0

3 years ago

Six over n equals twenty-one over twenty-eight<br> A. 13<br> B. 9<br> C. 8<br> D. 15

podryga [215]

C. Or 8, trust!!!!!!!!!

3 0

3 years ago

Surya is competing in a triathlon that includes swimming, bicycling and running. For the first two segments of the race, Surya s

Lorico [155]

1) 18.68 minutes

2) 2.34 %

3) 10.01 km/h

Step-by-step explanation:

In the first part (swimming part), Surya's velocity is

$v_1 = \frac{d_1}{t_1}= 4 km/h$

where

$d_1$ is the length of the swimming part

$t_1$ is the time taken to complete the swimming part

We can rewrite this equation as

$d_1 = v_1 t_1\\d_1 = 4t_1$ (1)

In the second part (biking part), Surya's velocity is

$v_2 = \frac{d_2}{t_2}=40 km/h$

where

$d_2$ is the length of the biking part

$t_2$ is the time taken to complete the biking part

We can rewrithe this equation as

$d_2=v_2 t_2\\d_2 = 40 t_2$ (2)

The total length of the two segments of the race is:

$d=d_1+d_2=43.29 km$ (3)

And the total time taken to complete them is

$t=t_1 + t_2 = 81.75 min \cdot \frac{1}{60}=1.36 h$ (4)

Substituting (1) and (2) into (3),

$4t_1+40t_2 = 43.29$ (5)

From (4), we find:

$t_2=1.36-t_1$

And substituting into (5), we can find t1, the time taken to complete the swimming part of the race:

$4t_1 +40(1.36-t_1) = 43.29\\4t_1 +54.5 -40t_1 = 43.29\\36t_1 = 11.21\\t_1=\frac{11.21}{36}=0.31 h \cdot 60 = 18.68 min$

In this part, we are told that the total distance covered by an athlete completing the swim + bycicle + run is

d = 52.95 km

This distance can be written as

$d=d_1+d_2+d_3$

where

$d_1$ is the length of the swimming part

$d_2$ is the length of the biking part

$d_3$ is the length of the running part

From the previous part, we can write the length of the swimming part as

$d_1 = v_1 t_1$

where:

$v_1=4 km/h$ is the velocity in the swimming part

$t_1=0.31 h$ is the time taken for the swimming part

So we have

$d_1 = (4)(0.31)=1.24 km$

So, the percent of the swimming part over the total is:

$\frac{d_1}{d}\cdot 100 = \frac{1.24}{52.95}\cdot 100 =2.34\%$

The total time for the entire race must be

$t=140 min \cdot \frac{1}{60}=2.33 h$

And this total time can be written as

$t=t_1+t_2+t_3$

where

$t_1$ is the time taken to complete the swimming part

$t_2$ is the time taken to complete the biking part

$t_3$ is the time taken to complete the running part

From part 1) we know that

$t_1=0.31 h$

and

$t_2=1.36-t_1=1.36-0.31=1.05 h$

So the time to complete the running part must be

$t_3=t-t_1-t_2=2.33-0.31-1.05=0.97 h$

The distance of the last segment is

$d_3=d-d_1 -d_2$

where $d_2$ is given by

$d_2=v_2 t_2 = (40)(1.05)=42 km$

So,

$d_3=52.95-1.24-42=9.71 km$

So the average velocity in the 3rd segment is

$v_3=\frac{d_3}{t_3}=\frac{9.71}{0.97}=10.01 km/h$

5 0

4 years ago