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3 years ago

What is the length of chord FL in A below?

Mathematics

2 answers:

telo118 [61]3 years ago

4 0

Answer:

Step-by-step explanation:

If you would rotate RN until R meets L it would exactly overlap with FL. So RN=FL.

Brrunno [24]3 years ago

3 0

Answer:

13.52

Step-by-step explanation:

If the distance between A and FL is the same between A and RN, you know that the angle between then is the same (90°). The two lines have the same lenght.

So, if RN is 13.52, FL is 13.52 too.

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A semicircle is attached to the side of a rectangle as shown.

laiz [17]

Answer:

$58.8\ mm^2$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of semicircle

step 1

Find the area of rectangle

The area of rectangle is equal to

$A=bh$

where

$b=9\ mm\\h=3\ mm$

substitute

$A=(9)(3)=27\ mm^2$

step 2

Find the area of semicircle

The area of semicircle is equal to

$A=\frac{1}{2}\pi r^{2}$

we have

$r=9/2=4.5\ mm$ ---> the radius is half the diameter

$\pi =3.14$

substitute

$A=\frac{1}{2}(3.14) (4.5)^{2}$

$A=31.8\ mm^2$

step 3

Find the area of the figure

$A=27+31.8=58.8\ mm^2$

4 0

3 years ago

Read 2 more answers

Solve the equation. -7= h/5 A. –35 B. 35 C. 12 D. -7/5

kkurt [141]

What does 7 represent

5 0

3 years ago

Can someone help me with this

SashulF [63]

Answer:

$\angle NRQ =85 \degree$

Given:

$\angle RPQ = 45 \degree \\ \angle PQR = (6x + 4)\degree \\ \angle NRQ = (15x - 5)\degree$

Step-by-step explanation:

Property used: An exterior angle of a triangle is equal to the sum of the opposite interior angles.

$= > \angle RPQ + \angle PQR = \angle NRQ \\ \\ = > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\ \\ = > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\ \\ = > 49\degree + 5 \degree= 15x\degree - 6x\degree \\ \\ = > 54\degree = 9x\degree \\ \\ = > 9x\degree = 54\degree \\ \\ = > x\degree = (\frac{54}{9} )\degree \\ \\ = > x\degree = 6\degree \\ \\ Putting \: value \: of \: x \: in \: \angle NRQ \\ \\ = > \angle NRQ = (15x - 5)\degree \\ \\ = > \angle NRQ = (15 \times 6 - 5) \degree \\ \\ = > \angle NRQ =85 \degree$

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3 years ago

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