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sergij07 [2.7K]
3 years ago
8

5. Estimate the value of √150 O between 5 and 6 O between 6 and 7 O between 7 and 8 O between 8 and 9​

Mathematics
1 answer:
Digiron [165]3 years ago
3 0

Answer:

basicaly your asking to be fulled so {{64

Step-by-step explanation:

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A cylinder has a radius of 12.2 inches and a height of 6.1 inches.
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How to find out L C M of common division method ​
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\huge\bigstar\:\Huge\tt\underline\blue{ANSWER}

To find Least Common Multiple by using Division Method we need to follow the following steps.

Step 1: Write the given numbers in a horizontal line, separating them by commas.

Step 2: Divide them by a suitable prime number, which exactly divides at least two of the given numbers.

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One quarter of a certain number added to one eighth of the same number is 12. What is the number​
alexdok [17]

Answer:

32

Step-by-step explanation:

let the number be n , then

\frac{1}{4} n + \frac{1}{8} n = 12 ( multiply through by 8 to clear the fractions )

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3n = 96 ( divide both sides by 3 )

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6 0
3 years ago
An urn contains two black balls and three red balls. If two different balls are successively removed, what is the probability th
lidiya [134]

You can extract two balls of the same colour in two different way: either you pick two black balls or two red balls. Let's write the probabilities of each pick in each case.

Case 1: two black balls

The probability of picking the first black ball is 2/5, because there are two black balls, and 5 balls in total in the urn.

The probability of picking the second black ball is 1/4, because there is one black ball remaining in the urn, and 4 balls in total (we just picked the other black one!)

So, the probability of picking two black balls is

P(\text{two blacks}) = \dfrac{2}{5} \cdot \dfrac{1}{4} = \dfrac{2}{20} = \dfrac{1}{10}

Case 2: two red balls

The probability of picking the first black ball is 3/5, because there are three red balls, and 5 balls in total in the urn.

The probability of picking the second red ball is 2/4=1/2, because there are two red balls remaining in the urn, and 4 balls in total (we just picked the other red one!)

So, the probability of picking two red balls is

P(\text{two reds}) = \dfrac{3}{5} \cdot \dfrac{1}{2} = \dfrac{3}{10}

Finally, the probability of picking two balls of the same colour is

P(\text{same colour}) = P(\text{two blacks})+ P(\text{two reds}) = \dfrac{1}{10} + \dfrac{3}{10} = \dfrac{4}{10} = \dfrac{2}{5}

7 0
3 years ago
Hey you click and answer :}
Contact [7]

Answer:

Hey :)

Step-by-step explanation:

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