Answer:
The speed increases by square root 2 times.
Explanation:
Let the wave velocity initially be 'v' with tension in the string as 'T' of mass 'm'.
Given:
Initial length of the string (L₁) = L
Final length of the string (L₂) = 2L
Wave velocity in a stretched string of length 'L' is given as:
From the above equation we can conclude that if tension 'T' and mass 'm' remains the same, the wave velocity is directly proportional to the square root of length of the stretched string. Therefore,
Now, plug in the given values and solve for v₂ in terms of v₁. This gives,
Therefore, the speed of the wave is increased by square root 2 times.
Well.....
Gravity from the sun pulls the planets torward it while inertia pulls it outward....but I guess that would be why it orbits sorry if this doesn't help but uh
Distance of first instance = speed * Time
= 60 * 3 = 180 miles
Distance of second instance = speed * Time
= 24 * 5 = 120 miles
So, Total Distance = 180 + 120 = 300 miles
In short, Your Answer would be 300 miles
Hope this helps!
Answer:
Explanation:
The formula for the potential energy of a dipole placed in an electric field is given by
U = - pE Cos θ
where, θ is the angle between dipole moment and the electric field vector.
For θ = 0°,
initial potential energy, Ui = - pE
For θ = 180°,
final potential energy, Uf = - pE Cos 180 = pE
Change in potential energy
ΔU = Uf - Ui
ΔU = pE - (-pE)
ΔU = 2pE
Answer:
7.78 * 10³ m/s
Explanation:
Orbital velocity is given as:
v = √(GM/R)
G = 6.67 * 10^(-11) Nm/kg²
M = 5.98 * 10^(24) kg
R = radius of earth + distance of the satellite from the surface of the earth
R = 2.15 * 10^(5) + 6.38 * 10^(6)
R = 6.595 * 10^(6) m
v = √([6.67 * 10^(-11) * 5.98 * 10^(24)] / 6.595 * 10^(6))
v = √(6.048 * 10^7)
v = 7.78 * 10³ m/s
