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sdas [7]
2 years ago
12

A small rocket to gather weather data is launched straight up. Several seconds into the flight, its velocity is 120 mis and it i

s accelerating at 18 mis 2. At this instant, the rocket's mass is 48 kg and it is losing mass at the rate of 0.50 kg/s as it burns fuel. What is the net force on the rocket?
Physics
1 answer:
padilas [110]2 years ago
8 0

The net force on the rocket is 864 N

Explanation:

The net force acting on the rocket can be calculated by using Newton's second law of motion, which states that:

F = ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the rocket in this problem, at a certain instant we have:

m = 48 kg

a=18 m/s^2

Therefore, the force on the rocket is

F=(48)(18)=864 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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I think its C. Oxygen 
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2 years ago
Given the information below, estimate the total distance travelled during these 6 seconds using a left endpoint approximation. t
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Answer:

184 feets

Explanation:

Given the data:

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0 __________30

1 __________ 54

2 __________56

3 __________34

4 __________ 8

5 __________ 2

6 __________22

Using left end approximation:

(0,1) ___ f(0) = 30

(1,2) ___ f(1) = 54

(2,3) ___f(2) = 56

(3,4) ___f(3) = 34

(4,5) ___f(4) = 8

(5,6) __ f(5) = 2

Hence, the Total distance traveled during the 6 second interval is:

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4 0
2 years ago
15 points for 2 questions
Elden [556K]
I believe the answer would be c because i think that you multiply the 2
8 0
2 years ago
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If the distance between slits on a diffraction grating is 0.50 mm and one of the angles of diffraction is 0.25°, how large is th
Trava [24]

Answer:

-  path differnce = 2.18*10^-6

-  1538 lines

Explanation:

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path\ difference\ = dsin\theta           (1)

d: separation between slits = 0.50mm = 0.50*10^-3 m

θ: angle of a diffraction = 0.25°

Then, the path difference is:

path\ difference\ =(0.50*10^{-3}m)sin(0.25\°)=2.18*10^{-6}m

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m: order of the bright

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The maximum bright is calculated for an angle of 90°:

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Answer:

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3.Only limited number of elements are known in an element whiles number of known compounds are quite large.

4.The property of an element is the property of the atom whiles the property of a compound is quite different from that of it's constituents.

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