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sdas [7]
3 years ago
12

A small rocket to gather weather data is launched straight up. Several seconds into the flight, its velocity is 120 mis and it i

s accelerating at 18 mis 2. At this instant, the rocket's mass is 48 kg and it is losing mass at the rate of 0.50 kg/s as it burns fuel. What is the net force on the rocket?
Physics
1 answer:
padilas [110]3 years ago
8 0

The net force on the rocket is 864 N

Explanation:

The net force acting on the rocket can be calculated by using Newton's second law of motion, which states that:

F = ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the rocket in this problem, at a certain instant we have:

m = 48 kg

a=18 m/s^2

Therefore, the force on the rocket is

F=(48)(18)=864 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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After a model rocket reached its maximum height, it then took 5.0 seconds to return to the launch site. what is the approximate
kifflom [539]
Air resistance is ignored.
g = 9.8 m/s².
At maximum height, the vertical velocity is zero.

Let h =  the maximum height reached.
Let u =  the vertical launch velocity.

Because ot takes 5.0 seconds to reach maximum height, therefore
(u m/s) - (9.8 m/s²)*(5 s) = 0 
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The maximum height reached is
h = (49 m/s)*(5 s) - (1/2)*(9.8 m/s²)*(5 s)²
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Answer: 122.5 m
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3 years ago
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vladimir2022 [97]

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3 years ago
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A stone is dropped from the upper observation deck of a tower, "500" m above the ground. (Assume g = 9.8 m/s2.) (a) Find the dis
Yuri [45]

Answer:

h₍₁₎ = 495,1 meters

h₍₂₎ = 480,4 m

h₍₃₎ = 455,9 m

...

..

Explanation:

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4 0
3 years ago
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The acceleration of the car will be needed in order to calculate the time. It is important to consider that the final speed is equal to zero:

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v = v_0 + at\ \to\ t = \frac{-v_0}{a} = \frac{-21.8\ m/s}{-2.4\ m/s^2} = \bf 9.08\ s

If you find some mistake in my English, please tell me know.
3 0
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