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sdas [7]
3 years ago
12

A small rocket to gather weather data is launched straight up. Several seconds into the flight, its velocity is 120 mis and it i

s accelerating at 18 mis 2. At this instant, the rocket's mass is 48 kg and it is losing mass at the rate of 0.50 kg/s as it burns fuel. What is the net force on the rocket?
Physics
1 answer:
padilas [110]3 years ago
8 0

The net force on the rocket is 864 N

Explanation:

The net force acting on the rocket can be calculated by using Newton's second law of motion, which states that:

F = ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the rocket in this problem, at a certain instant we have:

m = 48 kg

a=18 m/s^2

Therefore, the force on the rocket is

F=(48)(18)=864 N

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

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Two carts, one twice as heavy as the other, are at rest on a horizontal track. A person pushes each cart for 8 s. Ignoring frict
GalinKa [24]

Answer:

The correct option is: B that is 1/2 K

Explanation:

Given:

Two carts of different masses, same force were applied for same duration of time.

Mass of the lighter cart = m

Mass of the heavier cart = 2m

We have to find the relationship between their kinetic energy:

Let the KE of cart having mass m be "K".

and KE of cart having mass m be "K1".

As it is given regarding Force and time so we have to bring in picture the concept of momentum Δp and find a relation with KE.

Numerical analysis.

⇒ KE =  \frac{mv^2}{2}

⇒ KE =  \frac{mv^2}{2}\times \frac{m}{m}

⇒ KE =  \frac{m^2v^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(mv)^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(\triangle p)^2}{2}\times \frac{1}{m}

⇒ KE =  \frac{(\triangle p)^2}{2m}=\frac{(F\times t)^2}{2m}

Now,

Kinetic energies and their ratios in terms of momentum or impulse.

KE (K) of mass m.

⇒ K=\frac{(F\times t)^2}{2m}           ...equation (i)

KE (K1) of mass 2m.

⇒ K_1=\frac{(F\times t)^2}{2\times 2m}

⇒ K_1=\frac{(F\times t)^2}{4m}         ...equation (ii)

Lets divide K1 and K to find the relationship between the two carts's KE.

⇒ \frac{K_1}{K} =\frac{(F\times t)^2}{4m} \times \frac{2m}{(F\times t)^2}

⇒ \frac{K_1}{K} =\frac{2m}{4m}

⇒ \frac{K_1}{K} =\frac{2}{4}

⇒ \frac{K_1}{K} =\frac{1}{2}

⇒ K_1=\frac{K}{2}

⇒ K_1=\frac{1}{2}K

The kinetic energy of the heavy cart after the push compared to the kinetic energy of the light cart is 1/2 K.

7 0
3 years ago
How long does it take the earth to complete one revolution in seconds?
elena-s [515]
86,400 is the amount of seconds in a day. :)
3 0
3 years ago
Enrico is having trouble telling the difference between the sound of a tuba and the sound of a piccolo. Even though a piccolo pr
Nonamiya [84]

Answer: Pitch

Explanation:

Pitch of sound is defined as the factor that monitors the sound quality through produced vibrations rate.It helps in determination of sounds tone in terms highness or lowness.

According to the question,Enrico is finding difficulty in judging the difference between pitch sound of tuba and piccolo as per their tone in terms of high or low.

4 0
3 years ago
Imagine you are in an open field where two loudspeakers are set up and connected to the same amplifier so that they emit sound w
weeeeeb [17]

Question:

If you are 3.00 m from speaker A directly to your right and 3.50 m from speaker B directly to your left. What is the shortest distance d you need to walk forward to be at a point where you cannot hear the speakers?

Answer:

The shortest distance d you need to walk forward to be at a point where you cannot hear the speakers is 5.625 m

Explanation:

Shortest distance is given by

For constructive interference of wave, we have

\Delta r_{construct} = 2nλ/2

For destructive interference of wave, we have

\Delta r_{destruct} = (2n+1)λ/2

That is the difference in the number of wavelength between constructive and destructive interference is λ/2

We note that our positioning is 3.0 m from the first speaker and 3.5 m from the second, Which is of the form 2n and 2n + 1

Therefore when we walk forward away from the two speakers, we cannot hear the speakers at

Δr = λ/2 = r_B - r_A

Which is the distance between the points where we have constructive and destructive interference or where there is destructive interference between the waves

Where:

r_A =  Distance from  speaker A and

r_B = Distance from  speaker B

λ/2 = (344 m/s /688 Hz)/2

= 1/4

For

λ/2 = r_B - r_A  we have

√(3.5² +d²) - √(3²+d²) = 1/4

∴ d = 5.625 m

6 0
3 years ago
T/F The outer planets have solid surfaces that are very rocky and dense
Luba_88 [7]

Answer:

False

Explanation:

the inner planets have solid rocky dense surfaces

6 0
3 years ago
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