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sattari [20]
3 years ago
13

PLEASE HELP I WILL MARK YOU

Physics
1 answer:
DaniilM [7]3 years ago
7 0

We want to see if the Trust SSC can archive a higher maximum speed.

Remember the second Newton's law:

Force = mass*acceleration.

And acceleration is the rate of change of the velocity.

Assuming the mass of the Trust SSC does not change, increasing the force would mean that we increase the acceleration, and thus, <u>larger </u><u>velocities </u><u>can be reached.</u>

<u />

Now there are some problems.

How we do increase the force?.

It is hard to ve precise, mostly because we don't really know how the system works, we just got some given random data that we can't use without context.

Another thing we need to remember, this velocity is measured in only one mile. So because we have a<em> fixed distance to measure it</em>, we only can get larger velocities by increasing the acceleration.

And to increase the acceleration we can increase the force, as discussed, or, decrease the mass.

How to decrease the mass? Using lighter materials.

Now let's see an example on how decreasing the mass would affect the acceleration.

  • Mass = 10,700kg
  • Acceleration = 20.8 m/s^2

Then an aproximate force is given by:

F = 10,700kg*20.8 m/s^2 = 222,560 N

Now, if we decrease the mass a little bit, for example to 10,000kg, and we do not change the force, the new acceleration will be given by:

10,000kg*a = 222,560 N

a = (222,560 N)/(10,000kg) = 22.3 m/s^2

So decreasing the mass a little, increases the acceleration, which would make a larger maximum velocity.

Concluding, there are two ways of increasing the maximum velocity:

Increasing the force.

Decreasing the mass of the car.

If you want to learn more, you can read:

brainly.com/question/12550364

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It is force because work/distance= force
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3 years ago
A car traveling in a constant speed of 55km/h on a circular track what is the acceleration explain​
a_sh-v [17]

Answer:

See the explanation below

Explanation:

We must solve this problem by defining that when we have a constant velocity, the acceleration is equal to zero. That is, when there is no speed change, there is no acceleration. We can understand it very easily by means of the following equation of kinematics.

v_{f}=v_{o}+a*t

where:

Vf = final velocity = 55 [km/h]

Vo = initial velocity = 55 [km/h]

a = acceleration [m/s²]

t = time [s]

As we can see there is no change in speed, and the difference between the two is equal to zero.

0 = 0 +a*t\\a = (0-0)/t\\a= 0

3 0
3 years ago
If a machine is 100% efficient, MA is always less than VR.<br> Select one:<br> a. TRUE<br> b. FALSE
umka2103 [35]
True hope this helps you
5 0
3 years ago
An engineer is designing a spring to be placed at the bottom of an elevator shaft. If the elevator cable should happen to break
Anuta_ua [19.1K]

Answer:

k = 9876 N/m

Explanation:

As per energy conservation we know that

initial total gravitational potential energy = final spring potential energy

so we have

mg(h + x) = \frac{1}{2}kx^2

also we know that maximum acceleration will be 5.3 g

so it is given as

a = \frac{k}{m} x

so we have

x = \frac{ma}{k} = \frac{5.3 mg}{k}

mg(h + \frac{5.3 mg}{k}) = \frac{1}{2}k(\frac{5.3mg}{k})^2

mg(h + \frac{5.3 mg}{k}) = \frac{14.045(mg)^2}{k}

h + \frac{5.3mg}{k} = \frac{14.045 mg}{k}

h = \frac{8.745mg}{k}

k = \frac{8.745 (1439)(9.81)}{12.5}

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6 0
3 years ago
Suppose a planet is discovered by the Doppler technique and is then discovered to have transits. In that case, we can determine
vredina [299]

Answer:

option A

Explanation:

The correct answer is option A

Doppler technique is used in sound as well as light. Scientist uses this technique to study the universe by determining how fast stars and galaxies.

Transit is a phenomenon takes place when celestial body celestial passes directly between a larger body and the observer.

Using the Doppler effect we can determine the characteristics of the planet like the orbital period of the planet, size of the planet, mass and density of the planet.

The characteristics of the planet which we cannot find are The rotational period.

7 0
4 years ago
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