Answer:
We get 6 x10^7 with a 4dp of 9599
9599
/ \
29 331
Step-by-step explanation:
Rounded to 4dp
64151584.9599
<h2>
Mishka's speed = 14 km/hr</h2><h2>
Current speed = 2 km/hr</h2>
Step-by-step explanation:
Let the speed of rowing be r and speed of current be c.
If he rows with the current, Mishka rows 48 km in 3 hours.
Relative speed = r + c
Distance = 48 km
Time = 3 hours
48 = 3 x ( r+c)
r + c = 16 ---------------------------eqn 1
If he rows against the current, it takes 4 hours to travel the same distance.
Relative speed = r - c
Distance = 48 km
Time = 4 hours
48 = 4 x ( r - c)
r - c = 12 ---------------------------eqn 2
eqn 1 + eqn 2
2r = 28
r = 14 km/hr
Substituting in eqn 1
14 + c = 16
c = 2 km/hr
Mishka's speed = 14 km/hr
Current speed = 2 km/hr
Experimental Probability = 2/3
To find the experimental probability that the tack lands point-up for student 4, we can use the following equation

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Answer:
28"
Step-by-step explanation:
the length of the other non-hypotenuse side =
√(53² - 45²) =√(2809-2025) =√784 = 28"
Answer:
k = 4/5
Step-by-step explanation:
First, rewrite 5/6k as (5/6)k; this is "five sixths of the variable k."
Next, identify the LCD. It is 6. Then the given equation becomes
5k + 4 = 8
Consolidate the constant terms:
5k = 4
Solve for k: k = 4/5