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natali 33 [55]
3 years ago
14

What type of ion would radium (88Ra) become when forming an ionic compound, and what would the oxidation number be?

Chemistry
1 answer:
REY [17]3 years ago
3 0

Answer:

The correct option is A

Explanation:

Radium is an atom with the atomic number of 88. It is a metal found in group 2 of the periodic table; meaning that it has two valence electrons in it's outermost shell. As a metal that wants to form an ionic compound, <u>radium would have to lose these two valence electrons to become a divalent positively charged cation</u> (Ra²⁺). Thus, the correct option is A

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Explanation:

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An empty erlenmeyer flask weighs 241.3 g. when filled with water (d = 1.00 g/cm3), the flask and its contents weigh 489.1 g. wha
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The volume of the flask would simply be equal to the volume of the water. And the mass of the water would be the difference after and before weigh.

mass of water = 489.1 g – 241.3 g

mass of water = 247.8 g

 

Therefore the volume of water (which is also the volume of the flask) is:

volume = 247.8 g / (1.00 g/cm^3)

volume = 247.8 cm^3

 

The total mass of the flash when filled with chloroform would be:

total mass with chloroform = 241.3 g + 247.8 cm^3 (1.48 g/cm3)

total mass with chloroform = 608.04 g

 

 

Answers:

volume = 247.8 cm^3

total mass with chloroform = 608.04 g

4 0
4 years ago
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