Question

A solution was found to have a 15. 6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path length of 5. 00 cm. Calculate the absorbance of the solution in a 1. 00 cm cell at 500 nm.

Answer 1

The correct answer is 0.16138

Solution:

Percentage transmission (%T) of the sample = 15.6

Therefore, Absorbance (A)  2 – log (%T) = 2 – log (15.6) = 0.8069

Use Beer’s law:

A = ε*c*l where ε = molar absorptivity of the solution, c = concentration of the solution, and l = path length of the solution.

Given A = 0.8069 and l = 5.00 cm, we must have

0.8069 = ε*c*(5.00 cm)

ε*c = 0.16138 cm-1

For the next part, assume that ε*c remains constant and we have

A’ = ε*c*l’ where l = 1.00 cm.

Plug in values and write

A’ = (0.16138 cm-1)*(1.00 cm) = 0.16138

The ratio of the light intensity entering the sample to the light intensity exiting the sample at a particular wavelength is defined as the transmittance. Absorption and transmission are two related and different quantities used in spectroscopy. The main difference between absorption and transmission is that absorption measures how much incident light is absorbed as it travels through the material, while transmission measures how much light is transmitted.

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