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skad [1K]
3 years ago
9

Ben uses a compass and a straightedge to construct ∠DEF ≅ ∠ABC, as shown below:

Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer: Choice D

∠DEF ≅ ∠ABC when BH = EJ, BI = EK, and HI = JK.

======================================================

Explanation:

Effectively what Ben is doing is ensuring that

  • BH = EJ
  • BI = EK
  • HI = JK

are the three congruent corresponding sides. This is by construction. After those constructions, he would use SSS to prove the triangles congruent. Lastly, he can then say angle DEF is congruent to angle ABC due to CPCTC.

CPCTC = corresponding parts of congruent triangles are congruent.

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A person who is 3 m tall casts a shadow that is 6 m long. At the same time, a building
podryga [215]

Answer:

13.5 meters

Step-by-step explanation:

25 / 2 = 13.5

because if a human is 3 meters tall and cast 2 times the length of himself then if a building casts 25 meters then it should be 2 times less than its shadow.

6 0
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Which statement correctly describes the relationship between the graph of f(x)=x and the graph of g(x)=f(x+9) ?
kumpel [21]

Answer:

okjrbuurifff f

Step-by-step explanation:

  1. niehfubft hid xd find
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6 0
3 years ago
Jackie earns 14% commission as a salesperson. She sold a sofa that costs $870. How much commission did Jackie earn?
Ivan

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Step-by-step explanation:

HE IS PORE THAT IS WHAT HE IS

7 0
2 years ago
What 2 numbers multiply to get 10 and add to get 7?
Xelga [282]
5x2=10
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5 0
2 years ago
Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A
gtnhenbr [62]

Answer:

A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}

Step-by-step explanation:

Given: \text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}, \text{A}=\left \{\text{q, s, u, w, y} \right \}, \text{B}=\left \{\text{q, s, y, z} \right \},

\text{C}=\left \{\text{v, w, x, y, z} \right \}.

To find: The elements in the set A \cup C.

Solution:

We have,

\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}

\text{A}=\left \{\text{q, s, u, w, y} \right \}

\text{B}=\left \{\text{q, s, y, z} \right \}

\text{C}=\left \{\text{v, w, x, y, z} \right \}

Now, A \cup C will contain all the elements in the set A and all the elements in set C.

So, A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}.

Hence, A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}.

7 0
2 years ago
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