F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Answer:
<u>First question answer:</u> The limit is 69
<u>Second question answer:</u> The limit is 5
Step-by-step explanation:
For the first limit, plug in
in the expression
, that's the answer for linear equations and limits.
So we have:

The answer is 69
For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value
into the simplified expression to get the correct answer. Shown below:

<em>Now putting 1 in
gives us the limit:</em>

So the answer is 5
The probability is 1/5 (or if you want it in decimals then it is 0.2) (if you want it in percent then it is 20%)
Hope that helped!!!
Answer:
Sales tax: $352.50
Final Cost: $5052.50
Step-by-step explanation:
Answer:
The answer is A
Step-by-step explanation:
10 divided by 5