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Drupady [299]
3 years ago
10

james earns $3,129 a month. He is saving 1/3 of his income each month for a down payment on his home at the end of the year. How

much money will james be saving each month?
Mathematics
2 answers:
g100num [7]3 years ago
7 0

Answer:

The answer is 1,043. (you could just use a calculator)

bazaltina [42]3 years ago
5 0

Answer:

1,043

Step-by-step explanation:

To find this, multiply 1/3 x the monthly income.

1/3(3,129)

1,043

-Xax

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IN ΔBCD line N is the perpendicular bisector of BC and line M is the perpendicular bisector of CD
Helga [31]

Answer:

Correct answer is D(the intersection of lines N and M)

Step-by-step explanation:

we Know that  circumcenter of a triangle is  point at which the perpendicular bisectors of the sides of a triangle intersect and which is equidistant from the three vertices. In other words circumcenter of a triangle is the center of the circle which  passes through the vertices of the triangle. It means, any side of the triangle will act as a chord of the circumcircle. Hence the circumcenter of a triangle must lie on the perpendicular bisectors of the sides. therefore the intersection of line N and M must be  circumcenter of the triangle.

I hope this answer will help you

4 0
3 years ago
Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m
laila [671]
Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of t_{ \frac{1}{2} } after t years is given by

N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\  \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\  \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\  \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>
5 0
3 years ago
If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc
grin007 [14]

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112

3 0
3 years ago
Y=20+6x <br> x=150-4x<br> Solve with equal values method
katen-ka-za [31]

Step-by-step explanation:

Identify the method that will be used to solve for x for each equation.

4x=20 division property  fo equality

x-11=9 addition property of eqaulity

5x+6x=22 Combining Like terms

5(x-2)=30 distibute property

HOPE THIS HELPS!!!!!!!!

//////////////////////////////////////////////////////////////////////////////////////////////////////////////

4 0
3 years ago
Simplify give ur answer in index form.​
kherson [118]

\frac{( {j}^{4} \:  \times  \:  {j}^{8}) ^{3}  }{( {j}^{9} \:  \div  \:  {j}^{2}) ^{2}   }

  • First we calculate the product of the denominator.

\frac{( {j}^{12}) ^{3}  }{( {j}^{9} \:  \div  \:  {j}^{2}) ^{2}   }

  • Then we calculate the quotient of the numerator.

\frac{( {j}^{12}) ^{3}  }{( {j}^{7}) ^{2}   }

  • We multiply the exponents of the expression.

\frac{ {j}^{36} }{ {j}^{14} }

  • We divide.

\boxed{ \bold{ {j}^{22} }}

<h3><em><u>MissSpanish</u></em></h3>

3 0
2 years ago
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