Answer:
B. oxidation; reduction
Explanation:
A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.
1. This cell utilizes chemical reaction to generate electric.\
2. there two electrode anode and cathode
3. At Anode oxidation occurs
4. At cathode reduction occurs
5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.
- oxidation is the process in which there is loss of electrons
- Reduction is the process in which there is gain of electrons
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Based on above discussion
At anode oxidation takes place
At cathode reduction takes place.
Hence, correct option is B. oxidation; reduction
Answer of this question is D
Answer:
Ka = 4.76108
Explanation:
- CO(g) + 2H2(g) ↔ CH3OH(g)
∴ Keq = [CH3OH(g)] / [H2(g)]²[CO(g)]
[ ]initial change [ ]eq
CO(g) 0.27 M 0.27 - x 0.27 - x
H2(g) 0.49 M 0.49 - x 0.49 - x
CH3OH(g) 0 0 + x x = 0.11 M
replacing in Ka:
⇒ Ka = ( x ) / (0.49 - x)²(0.27 - x)
⇒ Ka = (0.11) / (0.49 - 0.11)² (0.27 - 0.11)
⇒ Ka = (0.11) / (0.38)²(0.16)
⇒ Ka = 4.76108
It can be either they can have a negative or positive charge more specifically negatively charged molecule would called an anion and a positive one would be cation.
