Explanation:
a)element=argon
number of electrons=18
it's an inert gas,thus it is fully filled
b)element=cobalt
number of electrons=27
valence electron=1
c).element=nitrogen
number of electrons=7
valence electrons=3
d)element=stanium
number of electrons=50
valence electrons=2
Metallic bonding is the answer to your question.
All metals, which have metallic bonding existing in them, are malleable, which means they can be easily change shape without breaking their bonding.
To understand the reason behind this property, we have to know what a metallic bonding is. Metallic bond is the non directional electrostatic force (attraction force) existing between metal cations (atoms but with fewer electrons), and the sea of the delocalised electrons (from the atom itself). Since metallic bond is strong, and the ions are packed regularly, the structure cannot be broken easily.
Once we apply pressure to the metal, the ions adapt a new position and stays in that new shape, thus, we say metals are malleable.
It is to make food. I hope this helps tell me if i'm wrong.
1) You neeed to know and use the Ksp for BaF2.
At 25°C this Ksp is 1.0 * 10 ^ - 6
2) The solutibility of BaF2 is given by:
BaF2 ⇄ Ba(2+) + 2F(-)
x 2x
=> Ksp = x * (2x)^2 = 4x^3
3) When you have a NaF solution, you have to take into accout the concentration of the NaF solution
M = 0.1
Now the equilibrium species are:
BaF2 ⇄ Ba(2+) + 2F(-)
x 2x + 0.10
And Ksp = x* [2x + 0.10]^2 = 1.0 * 10 ^ -6
Given that the Ksp << 1 you may assume that 2x << 0.1 => 2x + 0.1 ≈ 0.1
=> 1.0 * 10 ^ - 6 ≈ x(0.1)^2 = 0.01x
=> x = 1.0 * 10^ -6 / 0.01 = 1.0 * 10^ - 4 M = 0.0001 M
That is the molar solubility.
4) Now, you calculate the number of moles from the molarity's formula:
M = n / v => n = M * v = 0.0001 M * 0.500 l = 0.00005 mol
And now convert to grams,
mass in grams = number of moles * molar mass
molar mass of BaF2 = 175.34 g/mol
mass in grams = 0.00005 moles * 175.34 g / mol = 0.0088 g
Answer: 0.0088 g
The answer to number 14 is 60 percent.